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7. General Energy Equation Example 7.1 O P=296 kPa The volume flow rate through the pump shown in Fig. 7.8 is 0.014m/s. The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by the check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86NM/N. 2-in Schedule 40 steel pipe Flow L0m Check valve 3-in Schedule 40 steel pipe PA-28 AP Pump Using the sections where the pressure gages are located as the sections of interest, write the energy equation for the system, including only the necessary terms, ods Pearson Eacation South Asia Pe Lad

7. General Energy Equation Example 7.1 O P=296 kPa The volume flow rate through the pump shown in Fig. 7.8 is 0.014m/s. The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by the check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86NM/N. 2-in Schedule 40 steel pipe Flow L0m Check valve 3-in Schedule 40 steel pipe PA-28 AP Pump Using the sections where the pressure gages are located as the sections of interest, write the energy equation for the system, including only the necessary terms, ods Pearson Eacation South Asia Pe Lad

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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7. General Energy Equation Example 7.1 OP= 296 kPa The volume flow rate through the pump shown in Fig. 7.8 is 0.014m3/s. The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by the check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86NM/N. 2-in Schedule 40 steel pipe Flow 10m Check valve 3-in Schedule 40 steel pipe PA-28 LPa Pump Using the sections where the pressure gages are located as the sections of interest, write the energy equation for the system, including only the necessary terms, zo06 Pearson Education South Asia Pie Lid
Transcribed Image Text:7. General Energy Equation Example 7.1 OP= 296 kPa The volume flow rate through the pump shown in Fig. 7.8 is 0.014m3/s. The fluid being pumped is oil with a specific gravity of 0.86. Calculate the energy delivered by the pump to the oil per unit weight of oil flowing in the system. Energy losses in the system are caused by the check valve and friction losses as the fluid flows through the piping. The magnitude of such losses has been determined to be 1.86NM/N. 2-in Schedule 40 steel pipe Flow 10m Check valve 3-in Schedule 40 steel pipe PA-28 LPa Pump Using the sections where the pressure gages are located as the sections of interest, write the energy equation for the system, including only the necessary terms, zo06 Pearson Education South Asia Pie Lid
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