27. DNA synthesis Suppose that upon synthesizing a molecule of DNA, you introduce a wrong base pair, on average, every 1000 base pairs. Suppose you synthesize a DNA molecule that is 1000 bases long.(a) Calculate and draw a bar graph indicating the yield (probability) of each product DNA, containing 0, 1, 2, and 3 mutations (wrong base pairs).(b) Calculate how many combinations of DNA sequences of 1000 base pairs contain exactly 2 mutant base pairs.(c) What is the probability of having specifically the 500th base pair and the 888th base pair mutated in the pool of DNA that has only two mutations?(d) What is the probability of having two mutations side-by-side in the pool of DNA that has only two mutations?

As per the given information,the probability of introducing a wrong base pair is the probability of…

Answered: 7. DNA synthesis Suppose that upon…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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On each trial of an experiment, a subject is presented with a constant soft noise, which is interrupted at some unpredictable time by a noticeably louder sound. The time it takes for the subject to react to this louder sound is recorded. The following list contains the reaction times (in milliseconds) for the 16 trials of this experiment: 285, 175, 164, 217, 273, 222, 212, 202, 236, 229, 171, 235, 193, 186, 261, 241 Send data to calculator th Find 40" and 75" percentiles for these reaction times. (a) The 40 th percentile: || milliseconds (Ь) The 75 th percentile: milliseconds
An article reports on an experiment in which each of five groups consisting of six rats was put on a diet with a different carbohydrate. At the conclusion of the experiment, the DNA content of the liver of each rat was determined (mg/g liver), with the following results: Carbohydrate Xi. Starch 2.58 Sucrose 2.63 Fructose 2.13 Glucose 2.41 Maltose 2.49 Assume that EEx;;2 = 183.9. Construct at CI for ij e = µ1 - (H2 + µ3 + H4 + H5)/4 which measures the difference between the average DNA content for the starch diet and the combined average for the four other diets. (Use a 95% confidence interval. Round your answers to three decimal places.) mg/g liver
A lumber company has just taken delivery on a shipment of 10,000 2 x 4 boards. Suppose that 40% of these boards (4000) are actually too green to be used in first-quality construction. Two boards are selected at random, one after the other. Let A = {the first board is green} and B = {the second board is green}. (a) Compute P(A), P(B), and P(A n B) (a tree diagram might help). (Round your answer for P(A n B) to five decimal places.) P(A) = Р(B) %D P(A n B) = Are A and B independent? O Yes, the two events are independent. No, the two events are not independent. (b) With A and B independent and P(A) = P(B) = 0.4, what is P(A n B)? How much difference is there between this answer and P(A n B) in part (a)? There is no difference. There is very little difference. There is a very large difference. For purposes of calculating P(A n B), can we assume that A and B of part (a) are independent to obtain essentially the correct probability? Yes No (c) Suppose the lot consists of ten boards, of which…
H216T: Quantitative Reasoning II home >6.1:Counting zyBooks catalog CHALLENGE 6.1.1: Counting. ACTIVITY 380482232410dny Jump to level 1 Parents are having triplet babies and have put 4 unique name cards in a bowl. * When the first baby is born, a parent draws a card and gives the baby that name. * When the second baby is born, the parent draws a card from the remaining names. * When the third baby is born, the parent draws a card from the remaining names. How many combinations of names were possiblé for those three babies? 2 Ex: 12 Check Feedback? is section?, GI Provide feedback acer D.
A molecular biologist is studying the effectiveness of a particular enzyme to digest a certain sequence of DNA nucleotides. He divides six DNA samples into two parts, treats one part with the enzyme, and leaves the other part untreated. He then uses a polymerase chain reaction assay to count the number of DNA fragments that contain the given sequence. The results are as follows: 2 Sample 5 3 4 Enzyme present Enzyme absent 16 11 22 34 14 43 30 12 40 16 27 10 Find a 95% confidence interval for the difference between the mean numbers of fragments.
1.) Let arr86 be a binary variable equal to 1 if a man was arrested during 1986, and zerootherwise. You have a dataset of young men from California who were born in 1960 or1961 and have at least one arrest prior to 1986. You also have data on the proportion ofprior arrests that led to a conviction (pcnv), the average sentence served from priorconvictions in months (avgsen), months spent in prison since age 18 prior to 1986(tottime), months spent in prison in 1986 (ptime86), and the number of quarters (0 to 4)that the man was legally employed in 1986 (qemp86). You estimate the following linearprobability model (standard errors are in parentheses): arr86 = 0.441 - .162pcnv + .0061avgsen - .0023tottime (.017) (.021) (.0065) (.005) - .022ptime86 - .043qemp86 (.005) (.005) n= 2725R2=.0474 a) Interpret the coefficient on avgsen, commenting on both magnitude and significance. Based on these results, do longer sentences deter future crime?…
Approximately one-third of all human twins are identical (one-egg) and two thirds are fraternal (two-egg) twins. Identical twins are necessarily the same sex, with female and male being equally likely. Among fraternal twins, approximately one-fourth are both female, one-fourth are both male, and half are one female and one male. Finally, among all births in theUnited States, approximately 10 in 1000 are twin births. A = {a U.S. birth results in twin females} B = {a U.S. birth results in identical twins} C = {a U.S. birth results in twins} Find P(A ∩ B) Find P(A ∩ C). Find P(B ∩ C).
The table shows the leading causes of death in a certain country in a recent year. The population of the country was 311311 million. If you lived in a typical city of 500,000, how many people would you expect to die of cancercancer each year? Cause Deaths Cause Deaths Heart disease 596 comma 700596,700 Alzheimer's disease 84 comma 90084,900 Cancer 575 comma 300575,300 Diabetes 73 comma 40073,400 Chronic respiratory diseases 143 comma 100143,100 Pneumonia/Influenza 53 comma 40053,400 Stroke 128 comma 600128,600 Kidney disease 45 comma 30045,300 Accidents 122 comma 500122,500 Suicide 38 comma 60038,600 About people would be expected to die of cancer each year. (Type a whole number. Round to the nearest person as needed.)
Suppose that a group of illegal counterfeiters print 1,000 copies of fake $20 bills and introduces them into the economy. Suppose that each bill is used once per week (starting in week 1), and that each time a bill is used, it has a 1 in 5 chance of being detected as fake. If it is detected, it is removed. If not, it is used again. k n-1 (a) What does the expression E 1000 (" ) represent? Explain. n=1 Suggestion: If you are unsure, try writing out the expression for n = 1,2, 3 and consider what these might represent.
(6) Find the order of the following permutations: (a) (154)(254)(1234) E S5.
43. Six thousand light bulbs light a large hotel and casino marquee. Each bulb fails completely at random, and each has an average lifetime of 3,280 hours. Assuming that the marquee stays lit continuously and bulbs that burn out are replaced immediately, how many replacements must be made each year on the average? 44. The owner of the hotel mentioned in Problem 43 has decided that in order to decrease the number of burned-out bulbs, she will replace all 6,000 bulbs at the start of each year in addition to replacing the bulbs as they burn out. Comment on the effectiveness of this strategy.
On each trial of an experiment, a subject is presented with a constant soft noise, which is interrupted at some unpredictable time by a noticeably louder sound. The time it takes for the subject to react to this louder sound is recorded. The following list contains the reaction times (in milliseconds) for the 19 trials of this experiment: 171, 212, 285, 175, 202, 269, 193, 217, 164, 231, 261, 236, 186, 257, 271, 229, 250, 296, 226 Send data to calculator Find 20th and 75th percentiles for these reaction times. (If necessary, consult a list of formulas.) (a) The 20th percentile: milliseconds (b) The 75th percentile: milliseconds

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