7. A water treatment plant of 200 m³/ day uses an activated carbon, in columns, to reduce phenolfrom 130 (Co) to 10 (Ce) mg/L. The phenol adsorption isotherm using Pica is given below. Theamount of Pica needed daily350300250A. The carbon needed is 160.7 kg/dayB. The carbon needed is 1607 kg/dayC. The carbon needed is 96.9 kg/dayD. The carbon needed is 969 kg/dayy = 94.869 x0.19712001501005080 120 160 200 240 280 320 360 400Ce, mg/L6/6ш 'w/x ob0 40

Given, V = 200 m3/day or 200000 L/day Co = 130 mg/L Ce = 10 mg/L

7. A water treatment plant of 200 m³/ day uses an activated carbon, in columns, to reduce phenol from 130 (C.) to 10 (Ce) mg/L. The phenol adsorption isotherm using Pica is given below. The amount of Pica needed daily 350 300 250 y = 94.869 x0.1971 A. The carbon needed is 160.7 kg/day B. The carbon needed is 1607 kg/day C. The carbon needed is 96.9 kg/day D. The carbon needed is 969 kg/day 200 150 100 50 80 120 160 200 240 280 320 360 400 Ce, mg/L 6/6w 'w/xeb 0 40

7. A water treatment plant of 200 m³/ day uses an activated carbon, in columns, to reduce phenol from 130 (C.) to 10 (Ce) mg/L. The phenol adsorption isotherm using Pica is given below. The amount of Pica needed daily 350 300 250 y = 94.869 x0.1971 A. The carbon needed is 160.7 kg/day B. The carbon needed is 1607 kg/day C. The carbon needed is 96.9 kg/day D. The carbon needed is 969 kg/day 200 150 100 50 80 120 160 200 240 280 320 360 400 Ce, mg/L 6/6w 'w/xeb 0 40

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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