7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below:

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore waterpressureat points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below

7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total
stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In
each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are
given below:
Transcribed Image Text:7. A soil profile consisting of three layers is shown in the figure. Calculate the values of the total stress, effective stress ad pore water pressure at points A, B, C, and D for the following cases. In each case, plot the variations with depth. Characteristics of layers 1, 2, and 3 for each case are given below:
Layeı 1
B
Groundwater table
Layer 2
Layer 3
Dry sand
Sand
Clay
Rock
Layer no.
Soil parameters
Thickness
1
Н, — 7 ft
Ya = 110 lb/ft³
H¸ = 12 ft
Ysat = 121 lb/ft
%3D
3
Н, — 6 ft
Yat = 118 lb/ft3
%3D
1
н, — 5 m
e = 0.7; G, = 2.69
П, — 8 m
e = 0.55; G, = 2.7
%3D
3
H, = 3 m
w = 38%;e = 1.2
1
н, 3 3 m
Ya = 16 kN/m³
2
Н, — 6 m
Yat
18 kN/m³
3
Н, — 2.5 m
17 kN/m³
%3D
Ysat
2.
2.
Transcribed Image Text:Layeı 1 B Groundwater table Layer 2 Layer 3 Dry sand Sand Clay Rock Layer no. Soil parameters Thickness 1 Н, — 7 ft Ya = 110 lb/ft³ H¸ = 12 ft Ysat = 121 lb/ft %3D 3 Н, — 6 ft Yat = 118 lb/ft3 %3D 1 н, — 5 m e = 0.7; G, = 2.69 П, — 8 m e = 0.55; G, = 2.7 %3D 3 H, = 3 m w = 38%;e = 1.2 1 н, 3 3 m Ya = 16 kN/m³ 2 Н, — 6 m Yat 18 kN/m³ 3 Н, — 2.5 m 17 kN/m³ %3D Ysat 2. 2.
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