7. A poll sampled 1000 adults in the U.S. Of these people, 770 said that they enjoyed situationsin which they competed with other people. Can you conclude that the proportion of adults inthe U.S. that like to compete is less than 80% ? Use a significance level of a = 0.05.Step 1: State the null and alternative hypotheses.Step 2: Given the level of significance a = 0.05, determine the critical value associated with it.Step 3: Compute test statistic.Method 1: p-valueMethod 2: critical valueConclusion in a sentence (Specifically explain the answer in relation to the problem).

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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After visiting the Titanic, Captain Brain and Mr. Pinky are taking the Alvin submarine back to the surface of the water. They start 1900 meters below the surface of the water, and ascend at 62 meters per hour.Note: under the water is a negative number.Write an equation to model this situation (use mm for meters and hh for hours)
You wish to test the following claim (H) at a significance level of a = Ho: P1 = P2 Ha: P₁ P2 You obtain a sample from the first population with 122 successes and 438 failures. You obtain a sample from the second population with 63 successes and 304 failures. test statistic = p-value = [three decimal accuracy] 0.001. [four decimal accuracy]
You claim that the proportion of students who favored ONLINE ASSESSMENT over FACE-TO-FACE ASSESSMENT is 65% at a 5% significance level. From the analysis, the Z-test is 1.16. The correct conclusion is we have a. sufficient evidence to reject the claim. O b. insufficient evidence to reject the claim. O c. insufficient evidence to support the claim. O sufficient evidence to support the claim.
A tube of listerine tartar control toothpaste 4.2 ounces. As people use the toothpaste the amount remaining in any tube is random. Assume the amount of toothpaste remaining in the tube follows a uniform distribution. What is the probability that there is more than 1.5 ounces remaining in the tube?
The US Department of Energy reported that 45% of homes were heated by natural gas. A random sample of 348 homes in Oregon found that 156 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 1% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: P Test Statistic = =✓ ✓ OF H₁: P Based on the hypotheses, compute the following: p-value = 45 0° 45 OB vo
The accompanying table contains the data for the amounts (in oz) in cans of a certain soda. The cans are labeled to indicate that the contents are 16 oz of soda. Use the sign test and a 0.01 significance level to test the claim that cans of this soda are filled so that the median amount is 16 oz. If the median is not 16 oz, are consumers being cheated? Click the icon to view the data. What are the null and alternative hypotheses? O A. Ho: Median volume ≤ 16 oz H₁: Median volume = 16 oz C. Ho: Median volume = 16 oz H₁: Median volume # 16 oz Find the test statistic. Test statistic (Round to three decimal places as needed.) = More Info 15.6 16.0 16.1 16.1 407 15.7 (…) 16.1 15.9 19:3 15.8 16.5 15.8 15.7 15.9 OB. Ho: Median volume ≤ 16 oz H₁: Median volume > 16 oz O D. Ho: Median volume = 16 oz H₁: Median volume < 16 oz Volume (in ounces) 15.7 15.5 15.7 15.7 15.8 420 15.9 103 16.3 15.7 15.7 16.1 16.3 15.8 15.7 15.6 15.5 15.6 15.5 20 16.0 400 15.8 19:0 15.6 15.6 15.5 16.4 15.9 D - X
Imagine you're a researcher and you need to perform a one-sided test of an alternate hypothesis. You decide to conduct a significance test at the .05 level. Which of the following of ranges of z-scores would make the test statistic significant at .05 (one -tail) but not at .01 . A. z < 1.96 B. 1.645 < z < 1.70 C. z > 1.60 D. - 1.96 < z < 1.96 E 1.645 < z < 2.33
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The National Longitudinal Study of Adolescent Health interviewed several thousand teens (grades 7 to 12). One question asked was “What do you think are the chances you will be married in the next 10 years?” Here is a two-way table of the responses by gender: Opinion Female Male Almost no chance 120 94 Some chance but probably not 156 178 A 50-50 chance 427 498 A good chance 750 700 Almost certain 1176 770 How many individuals are described in this table? How many females were among the respondents? The percent of females among the respondents was about %. Your percent from the previous exercise is part of the marginal distribution of opinion about marriage. the conditional distribution of sex among adolescents with a given opinion. the marginal distribution of sex. What percent of females thought that they were almost certain to be married in the next 10 years?% Your percent from the previous exercise is part of the conditional distribution of sex among…
OI al College is less likely to attend orientation than men before they begin their coursework. A random sample of freshmen at Oxnard College were asked what their gender is and whether they attended orientation. The results of the survey are shown below: Data for Gender vs. Orientation Attendance Select an answer Women Men 439 242 What can be concluded at the a = 0.01 level of significance? For this study, we should use Select an answer a. The null and alternative hypotheses would be: Yes 350 No 262 Ho: Select an answer ✓ Select an answer ✓ Select an answer ✓ (please enter a decimal and note that p1 and μl represent the proportion and mean for women and p2 and μ2 represent the proportion and mean for men.) H₁: b. The test statistic ? | = c. The p-value d. The p-value is ? ✓ a e. Based on this, we should f. Thus, the final conclusion is that ... Select an answer ✓ Select an answer (Please enter a decimal) (please show your answer to 3 decimal places.) (Please show your answer to 4…
You wish to test the following claim (Ha) at a significance level of a = 0.002. Ho: P₁ P2 Ha P₁ P2 : You obtain a sample from the first population with 523 successes and 107 failures. You obtain a sample from the second population with 268 successes and 40 failures. test statistic = p-value [three decimal accuracy] [four decimal accuracy]
The US Department of Energy reported that 48% of homes were heated by natural gas. A random sample of 317 homes in Oregon found that 166 were heated by natural gas. Test the claim that proportion of homes in Oregon that were heated by natural gas is different than what was reported. Use a 5% significance level. Give answer to at least 4 decimal places. What are the correct hypotheses? (Select the correct symbols and use decimal values not percentages.) Ho: P Test Statistic = 0° p-value = H₁: p Based on the hypotheses, compute the following: #v oº 48 48 <-Need answer, please. <-Need answer, please OB 0° Based on the above we choose to Fail to reject the null hypothesis ✓ OB The correct summary would be: There is not enough evidence to support the claim that the proportion of homes in Oregon that were heated by natural gas is different than what the DOE reported value of 48%.

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