Floretta, a golfer, claims that her drive distance is not equal to 238 meters, on average. Several of her friends do notbelieve her, so she decides to do a hypothesis test, at a 5% significance level, to persuade them. She hits 19 drives,collects the proper data, and works through the testing procedure:• Hou = 238; HH #238• a = 0.05 (significance level)The test statistic isX-HoZo ==256-23814V19<= 5.6• The critical values are -20.025 = -1.96 and 20.025 = 1.96.Conclude whether to reject or not reject Ho. and interpret the results.Select the correct answer below:Reject Ho. At the 5% significance level, the test results are not statistically significant and at best, provide weakevidence against the null hypothesis.Reject Ho. At the 5% significance level, the data provide sufficient evidence to conclude that the mean distanceis not equal to 238 meters.Do not reject Ho. At the 5% significance level, the test results are not statistically significant and at best,provide weak evidence against the null hypothesis.Do not reject Ho. At the 5% significance level, the data provide sufficient evidence to conclude that the meandistance is not equal to 238 meters.

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Answered: Floretta, a golfer, claims that her…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The local Hannaford was tracking the proportion of customers who bought flour in their stores. In mid-March they found that 65% of customers were buying flour when it was available. They want to know if that percentage has decreased now that flour is more readily available. Their hypotheses are: Ho: ρ ≥ .65 and Ha: ρ < .65. They sample 200 customers and found that 120 of them bought flour. What is the computed test statistic? Calculate the z or t, whichever is appropriate, and give the result rounded to 2 decimal places. If it's a negative number, put the negative sign before the number with no spaces between it and the number.
14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…
Only about 15% of all people can wiggle their ears. Is this percent higher for millionaires? Of the 352 millionaires surveyed, 60 could wiggle their ears. What can be concluded at the a = 0.05 level of significance? a. For this study, we should use z-test for a population proportion v b. The null and alternative hypotheses would be: Ho: pv Select an answer v (please enter a decimal) H: pv Select an answer v (Please enter a decimal) c. The test statistic z v (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 3 decimal places.) e. The p-value is > vV a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly higher than 15% at a = 0.05, so there is statistically insignificant evidence to conclude that the population proportion of millionaires who can wiggle their ears is higher than 15%. O The data suggest the population…
A change is made that should improve student satisfaction with the parking situation at a local high school. Before the change, 37% of students approve of the parking that's provided. The null hypothesis Ho p> 0.37 is tested against the alternative Ho p = 0.37. The given hypotheses are incorrect. Give the correct hypotheses. Ho D= 0.37; H, > 0.37, where p the sample proportion of students at this high school that approve of the parking that is provided. Ho p = 0.37, H p> 0.37, where p = the true proportion of all students at this high school that approve of the parking that is provided. O H, ộ > 0.37, H, = 0.37, where p the sample proportion of students at this high school that approve of the parking that is provided. He: p = 0.37, H,: p 0.37, H. p< 0.37, where p = the true proportion of all students at this high school that approve of the parking that is provided.
The effectiveness of surgery for weight loss reported here found that "The surgery was associated with significantly greater weight loss [than the control group who dieted] through 2 years (61.3 versus 11.2 pounds, P<0.001)." What test could have been used and how would it have been computed?
please check this. The recidivism rate for convicted sex offenders is 14%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 324 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.05 level of significance? For this study, we should use The null and alternative hypotheses would be: Ho: (please enter a decimal) H1: (Please enter a decimal) The test statistic = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is αα Based on this, we should the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly different from 14% at αα = 0.05, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders…
For each of the tests, what would be the conclusion if the test were carried out using the α = 0.05 level of significance? H0 : µ = 120, H1:µ ≠ 120, n = 36, S.D of population= 10.3, sample mean = 117.0 Should the null be rejected?
Only about 15% of all people can wiggle their ears. Is this percent different for millionaires? Of the 398 millionaires surveyed, 40 could wiggle their ears. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer > < ≠ = (please enter a decimal) H1:H1: ? μ p Select an answer < = ≠ > (Please enter a decimal) The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer fail to reject accept reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population proportion is not significantly different from 15% at αα = 0.05, so there is statistically insignificant evidence to conclude that the…
The recidivism rate for convicted sex offenders is 12%. A warden suspects that this percent is different if the sex offender is also a drug addict. Of the 322 convicted sex offenders who were also drug addicts, 48 of them became repeat offenders. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use z-test for a population proportion V b. The null and alternative hypotheses would be: Ho: ? v Select an answer (please enter a decimal) H1: ? v Select an answer v (Please enter a decimal) c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value = (Please show your answer to 4 decimal places.) e. The p-value is ? V a f. Based on this, we should Select an answer v the null hypothesis. g. Thus, the final conclusion is that ... O The data suggest the population proportion is not significantly different from 12% at a = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of…
Can you please help me with this statistics last math problem? Thank you!
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The recidivism rate for convicted sex offenders is 14 %. A warden suspects that this percent is lower if the sex offender is also a drug addict. Of the 330 convicted sex offenders who were also drug addicts, 33 of them became repeat offenders. What can be concluded at the a = 0.10 level of significance? For this study, we should use Select an answer The null and alternative hypotheses would be: Select an answer Ho: ? ✓ H₁: ? ✓ Select an answer ✓ (please enter a decimal) (Please enter a decimal) The test statistic The p-value= The p-value is ? a Based on this, we should Select an answer the null hypothesis. Thus, the final conclusion is that ... (please show your answer to 3 decimal places.) (Please show your answer to 4 decimal places.) O The data suggest the populaton proportion is significantly lower than 14% at a = 0.10, so there is statistically significant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is…

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