7. A long slope is formed in a soil with shear strength parameters: and o' 0 and c' = 0 o' = 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat 18 kN/m³ and Y = 10 kN/m³. The maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would be

7. A long slope is formed in a soil with shear strength parameters: and o' 0 and c' = 0 o' = 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat 18 kN/m³ and Y = 10 kN/m³. The maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would be

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Question No. 16 A long slope is formed in a soil with shear strength parameters: c' = 0 and d' = 34°. A firm stratum lies below the slope and it is assumed that the water table may occasionally rise to the surface, with seepage taking place parallel to the slope. Use Ysat = 18 kN/m³ and Yw = 10 kN/m³. The maximum slope angle (in degrees) to ensure a factor of safety of 1.5, assuming a potential failure surface parallel to the slope, would be
7.17 A soil profile consists of a clay layer underlain by a sand layer, as shown in Figure P7.17. If a tube is inserted into the bottom sand layer and the water level rises to 1 m above the ground surface, determine the vertical effec- tive stresses and porewater pressures at A, B, and C. If K, is 0.5, determine the lateral effective and lateral total stresses at A, B, and C. What is the value of the pore- water pressure at A to cause the vertical effective stress there to be zero? GWL 11 m Y=18.5 kN/m? Clay 2 m Y= 19.0 kN/m³ 2: 1,5m Y =17.0 kN/m Sand 2 m FIGURE P7.17
Plot the distribution of total stress, effective stress, and pore- water pressure with depth for the soil profile shown in Figure PZ12. Neglect capillary action and pore air pressure. 4.5 m le=0.7, S= 0.85 5 m w 28% FIGURE P7.12
A 45 ° slope as shown in figure has been excavated to a depth of 6 m in a saturated clay having the following properties: C₁ = 50 kN/m² ₂ 0 = 0 and y = 19 kN/m²³ Determine the factor of safety. [Take area of wedge 39 m²] ok 3.4 m f 2.65 m 6m 45° 90° = 9m
Problem- For two infinite slopes (one in dry condition and other in submerged condition) in a sand deposit having the angle of shearing resistance 30°, factor of safety was determined as 1.5 (for both slopes). The slope angles would have been..
A 10m deep slope of 40° is made in saturated clay of unit weight 20kN/m3. The value of cohesion is given as 72 kN/m2 and the Taylor's stability coefficient is given as 0.18. Compute the factor of safety for the load.
7.8 [Use Eq. (7.26).] Figure P7.8 shows an embankment load on a silty clay soil layer. Determine the stress increase at points A, B, and C, which are located at a depth of 5 m below the ground surface.
A thin clay layer passes through the soil at an angle of 30° behind an 8m high gravity retaining wall. A structure 5m wide, applying a uniform stress of 40kPa to the sandy soil, also acts on this section of soil as shown in Figure 3.1. The properties of the clay are ??=25???, ∅?=0, ?′=0 and ∅′=20°. The sandy soil properties are ?′=0, ∅′=35°, ????=16??/?2, ????=20??/?2, and between the sand and the wall the properties are ?′?=0 and ∅′?=30°. Assuming that failure occurs along the clay layer, use Coulomb’s method to calculate the horizontal force required from the wall in the short term to prevent slip.
(Note:Depth of rock layer is 2m not 12 m.) Q A cut slope was excavated in a saturated clay with a slope angle β = 57 ͦ with the horizontal. Slope failure occurred when the cut reached a depth of 8 m. Previous soil explorations showed that a rock layer was located at a depth of 2 m below the ground surface. Assuming an undrained condition and that ɣsat = 21 kN/m3 : Determine the undrained cohesion of the clay (Fig 3). What was the nature of the critical circle? With reference to the top of the slope, at what distance did the surface of the sliding intersect the bottom of the excavation?
From the figure shown the soil has a unit weight of 28.5 kN/m^3 and the undrained shear strength cu = 20 kN/m^2. The slope makes an angle 62 degrees with the horizontal. Assume a stability number m = 0.16761. Compute the stability factor. a. 6.78b. 6.7c. 5.99d. 5.012. Compute the maximum depth up to which the cut could be made. a. 5.18 mb. 4.97 mc. 4.20 md. 3.84 m3. Compute angle that the failure plane makes with the horizontal if BC is 9 m. a. 22.32 degreesb. 28.25 degreesc. 21.05 degreesd. 20.15 degrees
3 of earth pressure at rest, active earth pressure and passive earth pressure. Write a note on Rankine's Earth Pressure Theory for Cohesive Soil Explain the Coulomb Wedge theory to estimate the earth pressure. 4 5 A soil mass is retained by a smooth backed vertical wall of 6m height. The unit weight of 20 KN/m3 and -16° The top of soil is level with the top of horizontal. If the soil surface carries a uniformly distributed load of 4.5 KN the total active thrust on the wall and its point of location. 6 Compute the intensity of passive earth pressure at a depth of 8m in a cohes with an angle of internal friction of 30° when water rises to the ground leve weight of sand is 21 KN/m³, Yw=9.81 KN/m³ 7 Compute the intensities of active and passive earth pressure at depth of 8m cohesionless sand with an angle of internal friction of 30° and unit weight What will be the intensities of active and passive earth pressure if the water the ground level? Take saturated unit weight of sand as 22…
Problem- For two infinite slopes (one in dry condition and other in submerged condition) in a sand deposit having the angle of shearing resistance 30°, factor of safety was determined as 1.5 (for both slopes). The slope angles would have been..