For a clay slope of height 10 m, stability number 0.05, bulk density 20 kN/m² and cohesion 25kN/m², the critical height of the slope will be:
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- An infinite slope of clay soil has a slope of 29 degrees. The soil has a specific gravity of 2.7 and a void ratio of 0.47. The soil has a depth of 5m over ledge rock measured vertically. Effective friction angle and soil cohesion are 14 degrees and 25kPa respectively. Assuming the ground water table is in the ground surface, determine the limiting depth of this soil, measured vertically over ledge rock. A 1.25m B 5.95m 3.67m D 6.88mFor a clay slope of height 20 m, the stability number is 0.05, y 25 = kN/m³, and c = 30 kN/m², the critical height of slope is: 1, 30 m 2, 20 m 3. 24 m 4. 26 mA 10m deep slope of 40° is made in a saturated clay of unit weight 20kN/m3. The value of cohesion is given as 72 kN/m2 and the Taylor's stability coefficient is given as 0.18. Compute the factor of safety for the load.
- The soil of an 21 degree infinite slope is subjected to full depth seepage. The soil properties are as follows: Saturated weight is 19 kN/m^3. Friction angle is 19 degrees Cohesion is 20 kN/m^2. Unit weight of water is 10 kN/m^3 Limiting depth of slope is (m) 2.96 m 4.95 m O 5.47 m 8.20 m1. Determine the gradient of each point from point 1. ( 2540 2540 2290 650-m from point 1-2 850-m from point 1-3 1550-m from point 1-4 Contour map units: meters 2. Given a density of a cubical quart rock to be 2650 kg/m³, determine the lithostatic stress on 800,000 cm³ volume if the acceleration is 980 cm/sec² with a depth of burial to be 6 miles./3 A soil profile consists of a clay layer underlain by a sand layer, as shown in the figure. If a tube is inserted into the bottom sand layer and the water level rises above the ground surface, Determine the effective vertical stress in kPa at B. * 3.2 m GWL ↑1 m Yst = 18.5 kN/m³ %3D Clay 2 m Ysat = 19.0 kN/m³ %3D |1.5 m Ysat = 17.0 kN/m³ %3D Sand В 2 m The value must be a number
- A fully submerged infinite sandy slope has an inclination of 30° with the horizontal. The saturated unit weight and effective angle of internal friction of sand are 18 kN/m² and 38°, respectively. The unit weight of water is 10 kN/m². Assume that the seepage is parallel to the slope. Against shear failure of the slope, the factor of safety (round off to two decimal places) is,The trapezoi dal earth embankment below has a unit weight of, Y = 17.25 KN/m3, determine the stress increase at pointA due to the embankment load A6z = KN/m2. The Slope on the rightis inclined at 1Vv: 1.5H and on the left is at 1V: 2 H. 7.50 m 9 m 25 meters:A cut slope was excavated in a saturated clay. The slope made an angle of 39.55 degree with the horizontal. Slope failure occurred when the cut reached a depth of 6 m. Previous soil explorations showed that a rock layer was located at a depth of 10 m below the ground surface. Assuming an undrained condition and γsat = 18 kN/m3, Analyze the following. a. undrained cohesion of the clay.b. nature of the critical circle?c. With reference to the toe of the slope, at what distance did the surface of sliding intersect the bottom of the excavation?
- A soil having the average properties, bulk unit weight = 19 kN/m³; angle of internal friction = 25° and cohesion = 15 kPa, is being formed on a rock slope existing at an inclination of 35° with the horizontal. The critical height (in m) of the soil formation up to which it would be stable without any failure is (round off to one decimal place). [Assume the soil is being formed parallel to the rock bedding plane and there is no ground water effect.]The intensity of passive earth pressure at a depth of 6 m in a cohesionless soil with an angle of internal friction of 30° kN/m². when water rises to ground level is Take saturated unit weight of sand as 21 kN/m³ and y = 9.81 kN/m³. YCalculate the effective vertical stress at point A in the soil profile shown below (g=10m/s2) a. 105.9kPA b. 93.7kPA c. 106.1kPA a. 159.1kPA