What is the factor of safety of a slope behind a geomembrane-lined pond when it is empty if the soil fails under undrained conditions? The slope is 3H to 1V, 7.5-meters deep, and will be of the toe failure type (i.e., n = 1.0). The soil’s unconfined compressive strength is qu = 35 kN/m2 (note that qu = 2c) and its unit weight is 18 kN/m3. Show your work!
What is the factor of safety of a slope behind a geomembrane-lined pond when it is empty if the soil fails under undrained conditions? The slope is 3H to 1V, 7.5-meters deep, and will be of the toe failure type (i.e., n = 1.0). The soil’s unconfined compressive strength is qu = 35 kN/m2 (note that qu = 2c) and its unit weight is 18 kN/m3. Show your work!
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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- What is the factor of safety of a slope behind a geomembrane-lined pond when it is empty if the soil fails under undrained conditions? The slope is 3H to 1V, 7.5-meters deep, and will be of the toe failure type (i.e., n = 1.0). The soil’s unconfined compressive strength is qu = 35 kN/m2 (note that qu = 2c) and its unit weight is 18 kN/m3. Show your work!
**HINT: you will need to reference the figure below for your Ns value for “soils whose strength can be approximated by undrained conditions”.
![0.19
B = 53°
0.18
B = 45°
0.17
k = 3
30°
0.16
22.5°
2
0.15 -
0.14
0.13 -
Case 1
0.12
kH
H.
nH
D
0.11
Case 2-
0.10
nH
0.09
1
3
D + H
H
Figure 5.23 Stability curves for soils whose strength can be approximated by
undrained conditions. (After Taylor [47])
15°
H^12 = $N
I
B = 7.5°
k = 0
4)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb347987a-df3b-40b4-ae0b-f956b4f25ef7%2F19fc14d5-d899-409e-ab89-31877db8c73c%2Ffakiqar_processed.jpeg&w=3840&q=75)
Transcribed Image Text:0.19
B = 53°
0.18
B = 45°
0.17
k = 3
30°
0.16
22.5°
2
0.15 -
0.14
0.13 -
Case 1
0.12
kH
H.
nH
D
0.11
Case 2-
0.10
nH
0.09
1
3
D + H
H
Figure 5.23 Stability curves for soils whose strength can be approximated by
undrained conditions. (After Taylor [47])
15°
H^12 = $N
I
B = 7.5°
k = 0
4)
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