Please answer and explain! **Question:**A constant force of 25 N is applied as shown to a block which undergoes a displacement of 7.5 m to the right along a frictionless surface while the force acts. What is the work done by the force?A) zero joules B) +94 J C) −94 J D) +160 J E) −160 J**Diagram:**- A block is depicted on a flat, frictionless surface.- A force **F** of 25 N is applied at an angle of 30° from the horizontal.- The direction of displacement **s** is directly to the right.**Explanation of the Diagram:**- The force vector **F** is drawn at a 30° angle above the horizontal direction.- The displacement vector **s** is shown as a horizontal arrow pointing to the right.The task is to calculate the work done by the force on the block during the displacement.

It is believed that work done by a constant force can solve this problem. Calculate the angle between force and displacement using the relation between work done and force. Find the force's work by relating work done, force, and displacement.the angle between displacement and component of force along the direction of displacement is,θ=180−30°=150°Work done on an object by a constant force is given by,W = F×s =Fscosθ W=25N)(7.5m)cos(150° )W =−162.4J so the nearest value is -160J so the correct option is E )-160J

Science

Advanced Physics

7. A constant force of 25 N is applied as shown to a block which undergoes a displacem of 7.5 m to the right along a frictionless surface while the force acts. What is the worl done by the force? F A) B) C) D) E) 30° zero joules +94 J -94 J +160 J -160 J 152 S

7. A constant force of 25 N is applied as shown to a block which undergoes a displacem of 7.5 m to the right along a frictionless surface while the force acts. What is the worl done by the force? F A) B) C) D) E) 30° zero joules +94 J -94 J +160 J -160 J 152 S