7) Consider the following reaction: liter mol-sec 2 HI(g) → H₂(g) + I2 (g) Initially, a flask contained HI at a concentration of 0.670 M. At equilibrium, the concentration of [HI] in the flask was 0.125 M. From this information, answer the following questions: a. What is the equilibrium constant for the above reaction? b. What is the rate constant for the reverse reaction? Note: remember that ratef=rater, and assume this is a one-step mechanism (the reactions shown have the correct molecularity). Answer: 0.6, 0.06 k = 0.0969.
7) Consider the following reaction: liter mol-sec 2 HI(g) → H₂(g) + I2 (g) Initially, a flask contained HI at a concentration of 0.670 M. At equilibrium, the concentration of [HI] in the flask was 0.125 M. From this information, answer the following questions: a. What is the equilibrium constant for the above reaction? b. What is the rate constant for the reverse reaction? Note: remember that ratef=rater, and assume this is a one-step mechanism (the reactions shown have the correct molecularity). Answer: 0.6, 0.06 k = 0.0969.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Correct answers are given
![7) Consider the following
mechanism
0(g) + O₂(g)
2 NO₂(g)
at another te
C. Note: remember that r
alculate the numerical va
arium expression for the fon
ky = 4.1
ky= 26x10¹
(forward and reverse, resp
reaction:
2 HI(g) → H₂(g) + 12 (g)
Initially, a flask contained HI at a concentration of 0.670 M. At equilibrium,
the concentration of [HI] in the flask was 0.125 M. From this information,
answer the following questions:
a. What is the equilibrium constant for the above reaction?
b. What is the rate constant for the reverse reaction? Note: remember
that ratef = rater, and assume this is a one-step mechanism (the
reactions shown have the correct molecularity).
Answer: 0.6, 0.06
k = 0.0969
liter
mol-sec](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1077e877-4e25-45d6-8c49-9aaf109d8b6e%2F02e5e49e-f0c8-4d41-970b-d0abc30ff65f%2F8tgkksl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:7) Consider the following
mechanism
0(g) + O₂(g)
2 NO₂(g)
at another te
C. Note: remember that r
alculate the numerical va
arium expression for the fon
ky = 4.1
ky= 26x10¹
(forward and reverse, resp
reaction:
2 HI(g) → H₂(g) + 12 (g)
Initially, a flask contained HI at a concentration of 0.670 M. At equilibrium,
the concentration of [HI] in the flask was 0.125 M. From this information,
answer the following questions:
a. What is the equilibrium constant for the above reaction?
b. What is the rate constant for the reverse reaction? Note: remember
that ratef = rater, and assume this is a one-step mechanism (the
reactions shown have the correct molecularity).
Answer: 0.6, 0.06
k = 0.0969
liter
mol-sec
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