7) 7.5593 x 1038 atoms of vanadium will have a mass of 8) 7.5593 x 1038 atoms of vanadium is equal to 9) 3.7 moles of H₂O will have a mass of 10) 32,600 milligrams of carbon will contain 1.2556 67 1.63E+25 63.965 grams. moles of vanadium. grams. C atoms.
7) 7.5593 x 1038 atoms of vanadium will have a mass of 8) 7.5593 x 1038 atoms of vanadium is equal to 9) 3.7 moles of H₂O will have a mass of 10) 32,600 milligrams of carbon will contain 1.2556 67 1.63E+25 63.965 grams. moles of vanadium. grams. C atoms.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I need 7-10 put into a table just like answers 1 and 2.

Transcribed Image Text:Mixed Practice:
1) How many molecules of water are in 60.0 grams of it?
60.0g H₂0
2.01x10^24+
A
24
-2.01 x 10
molecules
2) How many grams does 4.77 x 1019 formula units of NaBr mass?
-0.00815g
04.77x1041²1
1 mol
6.022 X10 I mot
I mot H₂ 0 6.022 x10 mole
23
18.0158 ImoTH₂0
3) Which element has a molar mass of 196.97 g/mol? Au
4) Which element has a molar mass of about 83.8 g/mol?
5) Which diatomic element has a molar mass of 37.997 g/mol?
6) 6.02 x 1023 atoms of vanadium will have a mass of
7) 7.5593 x 1038 atoms of vanadium will have a mass of
8) 7.5593 x 1038 atoms of vanadium is equal to
9) 3.7 moles of H₂O will have a mass of
10) 32,600 milligrams of carbon will contain
1.2556
67
102.8999
1.63E+25
Kr
50.9
63.965
F
grams.
grams.
grams.
2.01 XID
moles of vanadium.
C atoms.
0.008155
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