7-63. The cotter is used to hold the two rods together.Determine the smallest thickness of the cotter and thesmallest diameter d of the rods. All parts are made of steelfor which the failure normal stress is oal - 500 MPa andthe failure shear stress is Tail - 375 MPa. Use a factor ofsafety of (F.S.), - 2.50 in tension and (ES.), - 1.75 in shear.30 kNDo mm40 mm30 kN

Given Applied force = 30 kN Maximum Normal stress = 500 Mpa Maximum Shear stress = 375 Mpa Factor of…

Answered: 7-63. The cotter is used to hold the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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7-63. The cotter is used to hold the two rods together. Determine the smallest thickness t of the cotter and the smallest diameter d of the rods. All parts are made of steel for which the failure normal stress is fail 500 MPa and the failure shear stress is fail 375 MPa. Use a factor of safety of (F.S.), = 2.50 in tension and (F.S.), = 1.75 in shear. -d- 30 kN 40 mm d - 30 kN t Prob. 7-63 10 mm =
Similar problem already solved on bartleby. Take reference from there.
The d = 17-mm-diameter solid rod passes through a D = 22-mm-diameter hole in the support plate. When a load P is applied to the rod, the rod head rests on the support plate. The support plate has a thickness of b = 10 mm. The rod head has a diameter of a = 34 mm, and the head has a thickness of t = 8 mm. The shear stress in the rod head cannot exceed 145 MPa, the punching shear stress in the support plate cannot exceed 100 MPa, and the bearing stress between the rod head and the support plate cannot exceed 145 MPa. Determine the maximum value of Pmax that can be supported by the structure.
The assembly consists of three disks A, B, and C that are used to support the load of 140 kN. Determine the smallest diameter d₁ of the top disk, and the largest diameter d₂ of the opening, and the largest diameter d3 of the hole in the bottom disk. The allowable bearing stress for the material is (b) allow = 350 MPa and the allowable shear stress is Tallow=125 MPa. C B d₁ -| A 140 kN 20 mm 10 mm d3 d2
FBD 3. Determine the required thickness of member BC and the diameter of the pins at A and B if the failure normal stress for member BC is Ofail = 30 ksi, and the failure shear stress for the pins is Tfail = 12 ksi. Use a safety factor of 1.2 to your design. Solution: 1.5 in. 60° 8 ft 5 kip/ft
The bell-crank mechanism is in equilibrium for an applied load of F1 = 17 kN applied at A. Assume a = 290mm, b = 120mm, c = 80mm, and e = 35°. Pin B is in a double-shear connection and has a diameter of 33 mm. The bell crank has a thickness of 36 mm. Determine (a) the shear stress in pin B. (b) the bearing stress in the bell crank at B. Bell crank F2 Support bracket A a Answers: Tpin B = MPa Ob = i MPa
An axial load is applied to the rectangular cross section bar which is welded at the 57 degree angle shown. If the weld material has a failure normal stress of 160 mPa and a failure shear stress of 90 mPa, determine the required thickness if a factor of safety of 2.3 is required. Also determine the required diameter of the bolts(to the nearest mm) if the plate is face bolted to the supports. The bolt material has a failure shear stress of 175 mPa.

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