6.27 Public Option, Part IlI: Exercise 6.13 presents the results of a poll evaluating support for thehealth care public option plan in 2009. 70% of 819 Democrats and 42% of 783 Independentssupport the public option.(a) Calculate a 95% confidence interval for the difference between (pp - Pi) and interpret it in thiscontext. We have already checked conditions for you.%) (please roundThe confidence interval is: (%,to the nearest percent) Interpret the confidence interval in context:95% of differences in proportions are contained within this intervalO We can be 95% confident that the difference in sample proportions is contained withinour intervalOWe can be 95% confident that the difference in population proportions is containedwithin our interval(b) True or false (Explain): If we had picked a random Democrat and a random Independent at thetime of this poll, it is more likely that the Democrat would support the public option than theIndependent.falsetrue

It is given that p1 hat is 0.7, p2 hat is 0.42, n1 is 819, n2 is 783 and level of confidence is…

Answered: 6.27 Public Option, Part IlI: Exercise…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The immunity rate for a person who received the vaccine was .07% (3 people out of 428 people) while the rate for those who were in the placebo group was 2.3% (10 people out of 426 people). Construct a 95% confidence interval for the difference in immunity rate between vaccine group and the placebo group.
We have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who are running a fever agree to take the new drug instead of the traditional treatment. Their temperatures are taken before the drug is administered and 30 minutes after taking the drug. The results are recorded in the Excel file below. Use the data to construct and interpret a 99% confidence interval for the mean change in temperatures of patients after taking this drug using Excel. Be sure to include any explanation necessary along with a sentence that explains what the interval means. First Temp Second Temp 100.1 98.9 101.3 99.1 102.1 99.2 102.7 99 101.9 98.7 100.8 98.6 103.1 99.4 102.5 99.2 103.5 100.1 101.7 99.2
A marketing study with a random sample of 400 results in 160 subjects reacting positively to the proposed product. Determine the 95% confidence interval for the population proportion.
A performance analyst simulated a computer system a total of 10 times, each simulation run independent of all the others. She calculated and recorded the sample means for system response time from each of the 10 runs, coming up with the following data: 2,5,17,3,9,6,4,25,8,1(a) What is the confidence interval with a 95% confidence level for the mean response time? (b) The performance analyst was concerned that the width of the confidence interval was too large, and consulted one of her colleagues (who never took simulation and modeling). He assured her that the width of the confidence interval was large because of the two large "outliers," the values 17 and 25, and that she could reduce the width of the confidence interval simply by discarding these values. She tried this, and discovered that the width of the interval did indeed go down substantially. Is this a valid method? Why or why not?
A computer store near campus is stocking its shelves and wants to know the relative proportions of students who use PCs vs Macs. A random sample of 60 students is surveyed, and each student is asked whether they use a PC or Mac more often. 55% select ”PC.” (a) What is the population and what is the sample in this study? (b) Calculate a 95% confidence interval for the proportion of UCI students that are PC users. (c) Provide an interpretation of this confidence interval in the context of this problem. (d) The confidence interval is pretty wide and leaves a lot of uncertainty over the proportion of UCIundergarduates who use PCs. With the goal to estimate a narrower 95% confidence interval, what is a simple change to this study that you could suggest for the next time that a similar survey is conducted?
How do I solve Part A?
A recent poll indicated that 42% of men supported raises taxes to fund additional park services. The poll also found that 64% of women supported such a tax. The sample consisted of 29 men and 25 women. Construct a 90% confidence interval around the difference in proportions.
Several years ago, 45% of parents who had children in grades K-12 were satisfied with the quality of education the students receive. A recent poll asked 1,025 parents who have children in grades K-12 if they were satisfied with the quality of education the students receive. Of the 1,025 surveyed, 484 indicated that they were satisfied. Construct a 99% confidence interval to assess whether this represents evidence that parents' attitudes toward the quality of education have changed.
Please help with A and B
How would i find: the 90% confidence interval is enter your response here <(p1−p2)< enter your response here.
in a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.- I need help with finding a 90% confidence interval for the population proportion (I also have to round the answer to three decimal places)

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