6.20 z-score for given probability in tails For a normal TRY distribution, a. Find the z-score for which a total probability of 0.02 falls more than z standard deviations (in either direction) from the mean, that is, below p Zo or above + zo. b. For this z, explain why the probability more than z standard deviations above the mean equals 0.01. c. Explain why +2.330 is the 99th percentile.

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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6.20 z-score for given probability in tails For a normal
TRY distribution,
a. Find the z-score for which a total probability of 0.02 falls
more than z standard deviations (in either direction)
from the mean, that is, below p
Zo or above + zo.
b. For this z, explain why the probability more than z
standard deviations above the mean equals 0.01.
c. Explain why +2.330 is the 99th percentile.
Transcribed Image Text:6.20 z-score for given probability in tails For a normal TRY distribution, a. Find the z-score for which a total probability of 0.02 falls more than z standard deviations (in either direction) from the mean, that is, below p Zo or above + zo. b. For this z, explain why the probability more than z standard deviations above the mean equals 0.01. c. Explain why +2.330 is the 99th percentile.
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