6.14 Thermal decomposition of 5.0 metric tons of limestone to lime and carbon dioxide absorbs 9.0x10° kJ of heat. Convert this energy to (a) joules; (b) calories; (c) British thermal units.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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6.14 Thermal decomposition of 5.0 metric tons of limestone to
lime and carbon dioxide absorbs 9.0x10 kJ of heat. Convert this
energy to (a) joules; (b) calories; (c) British thermal units.
6.15) At constant temperature, a sample of helium gas expands from
922 mL to 1.14 L against a pressure of 2.33 atm. Find w (in J) done
by the gas (101.3 J=1 atm-L).
6.16 The external pressure on a gas sample is 2660 mmHg, and
the volume changes from 0.88L to 0.63 L at constant temperature.
Find w (in kJ) done on the gas (1 atm·L = 101.3 J).
%3D
Problems in Context
6.17 The nutritional calorie (Calorie) is equivalent to 1 kcal. One
pound of body fat is equivalent to about 4.1x10° Calories. Express
ioulog ond kilojoules
Transcribed Image Text:alt fn Change 6.14 Thermal decomposition of 5.0 metric tons of limestone to lime and carbon dioxide absorbs 9.0x10 kJ of heat. Convert this energy to (a) joules; (b) calories; (c) British thermal units. 6.15) At constant temperature, a sample of helium gas expands from 922 mL to 1.14 L against a pressure of 2.33 atm. Find w (in J) done by the gas (101.3 J=1 atm-L). 6.16 The external pressure on a gas sample is 2660 mmHg, and the volume changes from 0.88L to 0.63 L at constant temperature. Find w (in kJ) done on the gas (1 atm·L = 101.3 J). %3D Problems in Context 6.17 The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about 4.1x10° Calories. Express ioulog ond kilojoules
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