6. Use the e, 8 definition to show that lim,2 x + 1 x+ 3 emlin

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Chapter2: Second-order Linear Odes
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Numerical Analysis 

**Problem 6**: Use the \( \epsilon, \delta \) definition to show that 

\[
\lim_{x \to 2} \frac{x+1}{x+3} = \frac{3}{5}.
\]

**Instructions**: 

1. Given a small positive number \( \epsilon \), find a corresponding \( \delta > 0 \) such that whenever \( 0 < |x - 2| < \delta \), it follows that 

   \[
   \left| \frac{x+1}{x+3} - \frac{3}{5} \right| < \epsilon.
   \]

2. Solve the inequality for \( x \) to determine \( \delta \) in terms of \( \epsilon \).

3. Verify your solution by confirming that \( \delta \) works for specific values of \( \epsilon \).

Note: The concept involves making the expression \( \frac{x+1}{x+3} \) arbitrarily close to \( \frac{3}{5} \) by restricting how close \( x \) is to 2.
Transcribed Image Text:**Problem 6**: Use the \( \epsilon, \delta \) definition to show that \[ \lim_{x \to 2} \frac{x+1}{x+3} = \frac{3}{5}. \] **Instructions**: 1. Given a small positive number \( \epsilon \), find a corresponding \( \delta > 0 \) such that whenever \( 0 < |x - 2| < \delta \), it follows that \[ \left| \frac{x+1}{x+3} - \frac{3}{5} \right| < \epsilon. \] 2. Solve the inequality for \( x \) to determine \( \delta \) in terms of \( \epsilon \). 3. Verify your solution by confirming that \( \delta \) works for specific values of \( \epsilon \). Note: The concept involves making the expression \( \frac{x+1}{x+3} \) arbitrarily close to \( \frac{3}{5} \) by restricting how close \( x \) is to 2.
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