6. To purify water which has iodine in it, one can use extraction with CCI4. The equationcan be written as I2 (aq) S I2 (CCL). What is the partition coefficient?1b. K =.K=[1,L,a. K =с. К3.d. 1%3Dе.7. Consider the unbalanced chemical equationCaCO; + H3PO4smallest integer coefficients, the coefficient for CO, isCa3(PO4) 2 + CO2 + H2O. When the reaction is balanced witha. 1b. 3с. 5d. 7e. none of these Question 8For the following mechanismNO (8) + NO (B)는 N,02 (8)N,O2 (g)(fast equilibrium)NJO2 (B) + O2 (g) 스2 NO2 (8)2 NO2 (g)(slow)the rate law isa. rate = k,[N,02][0,]b. rate = k,[NO]²c. rate = k,[NO]² – k_1[N,02]%3Dd. rate = K2 k-1[NO]?[0,]e. cannot be determined

Partition coeffcient, K = Concentration of solute in organic phaseConcentration of solute in aqueous…

6. To purify water which has iodine in it, one can use extraction with CCl4. The equati can be written as I2 (aq) S 2 (CCL4). What is the partition coefficient? e. K=[1;L, b. K = c. K=- d. 1 a. K = - P 7. Consider the unbalanced chemical equation CACO3 + H3PO4 smallest integer coefficients, the coefficient for CO2 is Ca3(PO4) 2 + CO2 + H2O. When the reaction is balanced with a. 1 b. 3 с. 5 d. 7 e. none of these

6. To purify water which has iodine in it, one can use extraction with CCl4. The equati can be written as I2 (aq) S 2 (CCL4). What is the partition coefficient? e. K=[1;L, b. K = c. K=- d. 1 a. K = - P 7. Consider the unbalanced chemical equation CACO3 + H3PO4 smallest integer coefficients, the coefficient for CO2 is Ca3(PO4) 2 + CO2 + H2O. When the reaction is balanced with a. 1 b. 3 с. 5 d. 7 e. none of these

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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2. Set the two equations equal and isolate In Ksp on one side of the equals sign by dividing both sides by (-RT). AG=RT'In Ksp=AH-TAS/-RT AG=In KSR=AH-TAS/-RT| 3. Create a graph using Excel plotting In Ksp on the y-axis and 1/T (make sure the units for temperature are Kelvin) on the x-axis. I In KSP 0 0.0029 -0.5 -1 -1.5 -2 -2.5 -3 -3.5 -4 -4.5 -5 0.003 0.0031 0.0032 1/T 0.0033 0.0034 0.0035 y=-2738x+5.075 R² = 0.9845 0.0036 a. Use the value obtained for the slope of the graph to solve for AH° using the equation derived in Question 2.
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At 0°C and 1 bar, a monolayer of CO adsorbed on 1 g of Fe/Al2O3 catalyst occupies a volume of 4.25 cm3. What is the area of the catalyst? The area per adsorbed particle is 0.165 nm2. Give your answer in m2.
The following equation describes the dependence of the rate constant (k) with the temperature in dynamic NMR. kgTc -AG*. exp (- RT. k = C where kg and h are physical constants, R is the ideal gas constant, T. is the coalescence temperature and AG* is the activation energy? The following table shows the units of some of these parameters. Parameters Units k s-1 To K h Js R JK-' mol-! AG* J mol- Does k increase with AG*? Explain your answer.
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Partition coefficients (Kow = organic solvent concentration/aqueous concentration, usually reported as log Kow) are important for determining how efficiently organic compounds can be extracted from aqueous solutions. For example, consider the two substances below. Which will be more soluble in water? Hexamethylbenzene (log Kow = 6.41) O Diethyl ether (log Kow = 0.83)