when 8.4 mol of PCl5 (g) is mixed with 1.8 mol of PCl3 (g) and allowed to come to equilibrium in a 10 dm3container the amount of PCl5 (g) at equilibrium is 7.2 mol.     Kc =   (b) Explain the effect of the following changes below on the value of Kc:   Increasing temperature   Lowering the concentration

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Chapter1: Chemical Foundations
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(a) Calculate the value of Kc for the reaction:

PCl5 (g)                PCl3 (g)   + Cl2 (g)                 ΔH = Positive

 

Given that when 8.4 mol of PCl5 (g) is mixed with 1.8 mol of PCl3 (g) and allowed to come to equilibrium in a 10 dm3container the amount of PCl5 (g) at equilibrium is 7.2 mol.

 

 

Kc =

 

(b) Explain the effect of the following changes below on the value of Kc:

 

  • Increasing temperature

 

  • Lowering the concentration of chlorine (Cl2)

 

  • Addition of a catalyst 

 

 

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i believe your ans for Kc is incorrect 

with Kc = 0.05

Examples of cal. Kc.
Calculate the value of Kc for the reacher.
PCLSS
= P C3(g) + Cl₂(g).
Given that when 8.4 mol of PCs (s) is mixed
with 1-8 mor of PCL3(g) & allowed to come
to equilibrium in a 10dm³ container the
amount of PC`s(s) at equilibrum is 7.2 mol.
PCL5
- PCI 3
ndes initially 8.4
84-102
7-2
nores@eqmail.
Full conc in
mol/dm³
7-2
10.
13.29
+ Cl₂.
1.8.
(²+1.8) 1.2.
3.0/10
1-2
10.
= 0-72
0.30.
012.
kc = [PC13 ] [C1₂] = [03][012]=K=00
[PCL5]
En = takes in
Ex = gives
+
out.
ma
Transcribed Image Text:Examples of cal. Kc. Calculate the value of Kc for the reacher. PCLSS = P C3(g) + Cl₂(g). Given that when 8.4 mol of PCs (s) is mixed with 1-8 mor of PCL3(g) & allowed to come to equilibrium in a 10dm³ container the amount of PC`s(s) at equilibrum is 7.2 mol. PCL5 - PCI 3 ndes initially 8.4 84-102 7-2 nores@eqmail. Full conc in mol/dm³ 7-2 10. 13.29 + Cl₂. 1.8. (²+1.8) 1.2. 3.0/10 1-2 10. = 0-72 0.30. 012. kc = [PC13 ] [C1₂] = [03][012]=K=00 [PCL5] En = takes in Ex = gives + out. ma
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