6. The following data were obtained for the reaction: A → products. Determine the rate law for this reaction,including the value of k.[A] (M) time (s)0.80000.775400.750830.7251290.700179

Step 1: Validation given data set for Zero order reaction ;time (sec)[A],…

Answered: 6. The following data were obtained for…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A certain reaction is second order in N, and first order in H,. Use this information to complete the table below. Round each of your answers to 3 significant digits. [N] [H, initial rate of reaction х10 1.26 M 0.560 M 76.0 M/s | M/s 1.26 M 0.272 M | M/s 5.70 M 0.124 M
You and your lab partner are studying the rate of a reaction, A + B --> C. You make measurements of the initial rate under the following conditions: O [A] = 6.0 and [B] = 0.6 O [A] = 3.0 and [B] = 0.6 O [A] = 4.5 and [B] = 0.6 [A] = 1.5 and [B] = 1.2 O [A] = 3.0 and [B] = 1.8 [A] = 1.5 and [B] = 1.8 O [A] = 3.0 and [B] = 1.2 O [A] = 7.5 and [B] = 0.6 Rate = K[A][B][C] Rate = K[A][C] Experiment [A] (M) [B] (M) Rate (M/s) (a) Which of the following reactant concentrations could you use for experiment 3 in order to determine the rate law, assuming that the rate law is of the form, Rate = k [A]* [B]Y? Choose all correct possibilities. k[A]² [C] O Rate = K[A][C]² Rate = k[A]²[C]² Rate = k[A]³ [C] O Rate = K[A][C]³ 1 2 Rate = 1.5 3.0 (b) For a reaction of the form, A + B + C --> Products, the following observations are made: tripling the concentration of A increases the rate by a factor of 9, doubling the concentration of B has no effect on the rate, and doubling the concentration of C…
17. SHOW ALL YOUR WORK OGiven the following data, determine the order of the reaction with respect to NO(g). 2 NO(g) + Cl2(g)→ 2 NOCI(g) Experiment 1 [C2] (M) 0.0100 [NO] (M) Rate (M/s) 3.4 x 104 1.36 x 103 3.4 x 104 0.0300 0.0150 0.0150 0.0100 3 0.0400
Consider the table of data collected for the reaction A → Products. Determine the magnitude (value) of the reaction rate constant by graphing the data appropriately. The table: Time (s) [A] (M) 0.00 0.600 1.50 0.325 3.00 0.178 4.50 0.095 6.00 0.050 7.50 0.028 9.00 0.015
Experimental data for the reaction A + 2B → C have been plotted in the following three different ways. 0.05 -3.0 0.04 0.03 0.02 0.01 0 IvI 0 2 Time (s) 1/[A] 100 80 40 20 0 In[A] -3.5 -4.0 -4.5 -5.0 0 2 Time (s) 2 Time (s) What is the order of the reaction, and what was the initial concentration of A? O first-order, initial concentration = 10 M second-order, initial concentration = 10 M zero-order, initial concentration = 10 M O second-order, initial concentration = 0.1 M O first-order, initial concentration = 0.1 M
5. You studied the chemical reaction, 2NO2(g) → 2NO(g) + O2(g), at 25°C by monitoring the concentration of NO2(g) as a function of time and constructed the following graph. y= 0.5408x + 125.0 R2=0.998 Time (s) What is the rate constant for this reaction at 25°C? Include the proper units. (W/T) [(3)ONI/T
In a study to determine the rate of the following reaction: 2NO (g) + 0, (g) → 2NO, (g) the concentration of NO was 0.0450 Mat t = 5.0 s and 0.0225 Mat t= 650.0 s. What is the average rate of the reaction during this time period?
just need standard error for K
Consider this reaction: 2C1,0, g) → 2C1, (6) + 50, (g) At a certain temperature it obeys this rate law. rate = (0.36 Ms)[C1,0,1 %3D Suppose a vessel contains Cl,0, at a concentration of 0.630 M. Calculate how long it takes for the concentration of Cl,0, to decrease to 5.0% of its initial value. You may assume no other reaction is important. Round your answer to 2 significant digits.

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6. The following data were obtained for the reaction: A → products. Determine the rate law for this reaction, including the value of k. [A] (M) time (s) 0.800 0 0.775 40 0.750 83 0.725 129 0.700 179