6. The figures below show the equivalent circuit of a separately excited DC generator and the approximate relationship between the flux of main field and exciting current. The field current I can be regulated by the variable resistor Ry, and the battery voltage supplying power to the exciter is 12V. The armature resistance Ro is 20, and the load is 182. For the DC generator, we aim to keep the voltage across the load (RL) constant in different speed range conditions. In the beginning, the flux is 0.12 Wb, the DC generator speed is 1000 rpm, and the generated voltage E。 is 100 V. Calculate: (1) The current flowing through the load. (2) When the speed of generator changes to 1500 rpm, how should we adjust the exciting current Ix to ensure Ę is still 100 V. (Hint: E₁ = Zno/60) (3) When the speed of generator changes to 500 rpm, how should we adjust the exciting current Ix to ensure Eo is still 100 V. (Hint: Eo = Zno/60) Rf ww (Wb) 0.17 0.15 12 V 1x F ele 1 1 2 ell Eo Ro ww 9 w RL Ix (A)

6. The figures below show the equivalent circuit of a separately excited DC generator and the approximate relationship between the flux of main field and exciting current. The field current I can be regulated by the variable resistor Ry, and the battery voltage supplying power to the exciter is 12V. The armature resistance Ro is 20, and the load is 182. For the DC generator, we aim to keep the voltage across the load (RL) constant in different speed range conditions. In the beginning, the flux is 0.12 Wb, the DC generator speed is 1000 rpm, and the generated voltage E。 is 100 V. Calculate: (1) The current flowing through the load. (2) When the speed of generator changes to 1500 rpm, how should we adjust the exciting current Ix to ensure Ę is still 100 V. (Hint: E₁ = Zno/60) (3) When the speed of generator changes to 500 rpm, how should we adjust the exciting current Ix to ensure Eo is still 100 V. (Hint: Eo = Zno/60) Rf ww (Wb) 0.17 0.15 12 V 1x F ele 1 1 2 ell Eo Ro ww 9 w RL Ix (A)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Please solve this problem step by step and illustrate your answer properly. Write your answer in a piece of paper please. Box the final answer.
A shunt DC generator has no load terminal voltage of 140V. Armature resistance is 1ohm and shunt field resistance is 50ohms. Calculate: (i) Induced voltage (ii) A load is now connected to the terminals that starts drawing 2A current and terminal voltage drops to 130V. Calculate the new value of the induced voltage Make sure to draw equivalent circuits for (i) and (ii)
A 900 rpm, 4 pole lap wound shunt motor takes 300 A. The flux per pole is 0.02 Wb and the armature has 1500 conductors. The shunt field takes 4 A of current. Solve for back emf (V).
Plz answer all parts
A 4 pole dc shunt generator with a shunt field resistance of 100 ohm and an armature resistance of 1 ohm has 378 wave connected conductor in its armature. the flux per pole is 0.02wb, if the load resistance of 10 ohm is connexted across the aemature terminal and the generator driven at 1000rpm, calculate the power obsorbed by load
Q3/ ( a) A d.c. series generator has armature resistance is 0.5 ohm and series field resistance is 0.03 ohm. It drives a load of 50 A. If it has 6 turns/coil and total 540 coils on the armature and is driven at 1500 r.p.m. Calculate the terminal voltage at the load. Assume 4 poles, lap type winding, flux per pole as 2 mWb and total brush drop as 2 V. (b)/Explain briefly construction of D.C. machine and What are the functions of a Yoke in DC machines? Explain.
A d.c. shunt generator has a full load output of 10 kW at a terminal voltage of 240 V. The armature and the shunt field winding resistances are 0.6 and 160 ohms respectively. The sum of the mechanical and core-losses is 500 W. Calculate the power required, in kW, at the driving shaft at full load, and the corresponding efficiency.
In a DC generator, the effect of armature reaction on the main field is to * reverse it O distort it O reduce it O both (b) and (c)
Example : In a 110 V, d.c. compound generator, the resistance of the armature, shunt field and series field are 0.06 , 25 and 0.04 respectively. The load consists of 200 lamps each rated at 55 W, 110 V. Find the total e.m.f. generated and the armature current when the machine is connected in (a) long shun
A 4 pole, lap wound, d.c. generators has 42 coils with 8 turns per coils. It is driven at 1120 r.p.m. If useful flux per pole is 21 mWb, calculate the generated e.m.f. Find the speed at which it is to be driven to generate the same e.m.f. as calculated above, with wave wound armature.
A d.c.series generator has armature resistance of 0.5Q and series field resistance of 0.032.It drives a load of 50 A.If it has 6 turns/coil and total 540 coils on the armature and is driven at 1500 r.p.m.,calculate the terminal voltage at the load.Assume 4 poles, lap type winding, flux per pole as 2 mWb and total brush drop as 2 V.