6. Given that P(n) is the equation 1· (1!) +2 · (2!) +..+n· (n!) = (n + 1)! – 1, where n is -... an integer such that n > 1, we will prove that P(n) is true for all n > 1 by induction. (a) Base case: i. Write P(1). ii. Show that P(1) is true. In this case, this requires showing that a left-hand side is equal to a right-hand side. (b) Inductive hypothesis: Let k > 1 be a natural number. Assume P(k) is true. Write P(k). (c) Inductive step: i. Write P(k+1). ii. Use the assumption that P(k) is true to prove that P(k + 1) is true. (d) Explain why this shows that P(n) is true for all n > 1.

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Given that P(n) is the equation 1·(1!)+2· (2!) + ·
an integer such that n > 1, we will prove that P(n) is true for all n > 1 by induction.
6.
+n· (n!) = (n + 1)! – 1, where n is
(a) Base case:
i. Write P(1).
ii. Show that P(1) is true. In this case, this requires showing that a left-hand side is equal to a
right-hand side.
(b) Inductive hypothesis: Let k > 1 be a natural number. Assume P(k) is true. Write P(k).
(c) Inductive step:
i. Write P(k + 1).
ii. Use the assumption that P(k) is true to prove that P(k+1) is true.
(d) Explain why this shows that P(n) is true for all n > 1.
Transcribed Image Text:Given that P(n) is the equation 1·(1!)+2· (2!) + · an integer such that n > 1, we will prove that P(n) is true for all n > 1 by induction. 6. +n· (n!) = (n + 1)! – 1, where n is (a) Base case: i. Write P(1). ii. Show that P(1) is true. In this case, this requires showing that a left-hand side is equal to a right-hand side. (b) Inductive hypothesis: Let k > 1 be a natural number. Assume P(k) is true. Write P(k). (c) Inductive step: i. Write P(k + 1). ii. Use the assumption that P(k) is true to prove that P(k+1) is true. (d) Explain why this shows that P(n) is true for all n > 1.
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