6. Consider the adjacency list (list of neighbors) struct node int data; node * next; class Graph private: node neighborList[30]; int last; 3; Write a method to print the neighbors of a given node n, void Graph:print(int n) {??????}
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- In Java please help with the following: Sees whether this list is empty.@return True if the list is empty, or false if not. */ public boolean isEmpty(); } // end ListInterface Hint:Node class definition should look something like: public class Node<T> { T element; Node next; Node prev; public Node(T element, Node next, Node prev) { this.element = element;this.next = next;this.prev = prev; } }1- A new static method with one parameter which is a head node for a linked list of integers, the method should create a new linked list which is equivalent to the original list of integers but with all repetitions removed, the method's return value is a head reference for the new list. this is what I have but it's not removing repetitions. public static IntLinkedBag removeRepetition (IntLinkedBag b1) { IntNode next; IntNode head = null; LinkedList<Integer> s = new LinkedList<>(); IntNode new_list = new IntNode(0, null); IntNode now = head; IntNode prev = new_list; while (now!= null) { int x = now.data; if (s.contains(x)) { new_list = new_list.next; } else { s.add(x); new_list.next = new IntNode(x, now); new_list = new_list.next; } now = now.next; } return b1; } }…For any element in keysList with a value greater than 50, print the corresponding value in itemsList, followed by a comma (no spaces). Ex: If the input is: 32 105 101 35 10 20 30 40 the output is: 20,30, 1 #include 2 3 int main(void) { const int SIZE_LIST = 4; int keysList[SIZE_LIST]; int itemsList[SIZE_LIST]; int i; 4 6 7 8 scanf("%d", &keysList[0]); scanf ("%d", &keysList[1]); scanf("%d", &keysList[2]); scanf("%d", &keysList[3]); 10 11 12 13 scanf ("%d", &itemsList[0]); scanf ("%d", &itemsList[1]); scanf("%d", &itemsList[2]); scanf ("%d", &itemsList[3]); 14 15 16 17 18 19 /* Your code goes here */ 20 21 printf("\n"); 22 23 return 0; 24 }
- Please fill in the code gaps if possible. This problem has been giving me trouble. Any help is appreciated. public class Node { private String element; // we assume elements are character strings private Node next; /* Creates a node with the given element and next node. */ public Node(String s, Node n) { //fill in body } /* Returns the element of this node. */ public String getElement() { //fill in body } /* Returns the next node of this node. */ public Node getNext() { //fill in body } // Modifier methods: /* Sets the element of this node. */ public void setElement(String newElem) { //fill in body } /* Sets the next node of this node. */ public void setNext(Node newNext) { //fill in body } }Sorting Create a MyLinkedList class with inner Node class, data fields, and the insert(element) method. Implement a toString method to return all nodes in MyLinkedList. Implement a recursive sorting and a non-recursive sorting method.public class HashIntSet { private class Node{ public int data; public Node next; public Node(int value) { data = value; next = null; } public Node(int value, Node next) { data = value; this.next = next; } } private Node[] elements; private int size; public HashIntSet() { elements = new Node[10]; size = 0; } public int hash(int i) { return (Math.abs(i) % elements.length); } public void add(int value) { if(!contains(value)) { int h = hash(value); Node newNode = new Node(value); newNode.next = elements[h]; elements[h] = newNode; size++; } } public boolean contains(int value) { Node current = elements[hash(value)]; while(current != null) { if(current.data == value) { return true; } current = current.next; } return false; } public String toString() { String s = ""; for(Node n:elements) { Node current = n; while(current != null) { s += current.data + " "; current = current.next; }…
- Redesign LaptopList class from previous project public class LaptopList { private class LaptopNode //inner class { public String brand; public double price; public LaptopNode next; public LaptopNode(String brand, double price) { // add your code } public String toString() { // add your code } } private LaptopNode head; // head of the linked list public LaptopList(String fname) throws IOException { File file = new File(fname); Scanner scan = new Scanner(file); head = null; while(scan.hasNextLine()) { // scan data // create LaptopNode // call addToHead and addToTail alternatively } } private void addToHead(LaptopNode node) { // add your code } private void addToTail(LaptopNode node) { // add your code } private…PYTHON LAB: Inserting an integer in descending order (doubly-linked list) Given main.py and an IntNode class, complete the IntList class (a linked list of IntNodes) by writing the insert_in_descending_order() method to insert new IntNodes into the IntList in descending order. Ex. If the input is: 3 4 2 5 1 6 7 9 8 the output is: 9 8 7 6 5 4 3 2 1 _____________________________________________________________________________________ Main.py: from IntNode import IntNode from IntList import IntList if __name__ == "__main__": int_list = IntList() input_line = input() input_strings = input_line.split(' ') for num_string in input_strings: # Convert from string to integer num = int(num_string) # Insert into linked list in descending order new_node = IntNode(num) int_list.insert_in_descending_order(new_node) int_list.print_int_list() IntNode.py class IntNode: def __init__(self, initial_data, next = None,…class Queue { private static int front, rear, capacity; private static int queue[]; Queue(int c) { front = rear = 0; capacity = c; queue = new int[capacity]; } static void queueEnqueue(int data) { if (capacity == rear) { System.out.printf("\nQueue is full\n"); return; } else { queue[rear] = data; rear++; } return; } static void queueDequeue() { if (front == rear) { System.out.printf("\nQueue is empty\n"); return; } else { for (int i = 0; i < rear - 1; i++) { queue[i] = queue[i + 1]; } if (rear < capacity) queue[rear] = 0; rear--; } return; } static void queueDisplay() { int i; if (front == rear) { System.out.printf("\nQueue is Empty\n"); return; } for (i = front; i < rear; i++) { System.out.printf(" %d <-- ", queue[i]); } return; } static void queueFront() { if (front == rear) { System.out.printf("\nQueue is Empty\n"); return; } System.out.printf("\nFront Element is: %d", queue[front]);…
- 2) Suppose you have a linked list class that provides the following methods: // constructor. // returns size of the list. LinkList () int size (); void insertHead (Object data) // insert new data at the head of // the list. // remove and return the Object at // the head of the list. Object removeHead () void insertTail (Object data) // insert new data at the tail of // the list. The class below is an implementation of a stack using the linked list class. Fill in the method implementations: class Stack { private Stack s; public Stack () { public void push (Object x) { } public Object pop () // assume stack is not empty { } public boolean isEmpty() { }boɔ ypleð The following code shows how one might implement a binary tree node: public class TreeNode ( public int data; public TreeNode left; public TreeNode right; public TreeNode(int d, TreeNode 1, TreeNode r) { data = d; left - 1; right = r; Suppose we have the following binary tree (with root being the node at the top): 7 The following method is an instance method in the TreeNode class. public int c() { int leftc = 0; if (left != null) { leftc - left.c (); int rightc - 0; if (right != nul1) { rightC = right.c(); return leftc + rightC + 1; Suppose root.c() is called. What is returned? Show memory diagrams and/or stack frames to explain what the recursive calls are.1.Assume some Node class with info link fields . Complete this method in class List that returns a reference to the node containing the data item in the argument findThis, Assume that findThis is in the list public class list { protected Node head ; Protected int size ; Public Node find (char find this) { Node curr = head; while(curr != null) { if(curr.info == findThis) return curr; curr = curr.link; } return -1; } }