6. An anchored sheet pile wall is driven in clay. The soil profile and water table are shown in the following figure. The thickness of sand is 10 m, and its properties are ' = 30° y = 16.5 kN/m³, Ysat = 18.5 kN/m³. The properties of clay are C₁ = 45 kN/m², Ysat = 19.0 kN/m³. The surcharge on the surface is 200 kN/m². (1) Determine the theoretical depth of the sheet pile wall by using free earth support method. (2) Calculate the anchor force per unit length of the wall. q = 200 kN/m² Equations and Tables: K. 1-sino' K₁ = 0.95-sin ' 2 m Anchor Y = 16.5 kN/m³ 4 m Sand Water table '=30° Sand Ysat 18.5 kN/m³ 6 m 2' = 30° D Ysat 19.0 kN/m³ Clay C = 45 kN/m² Fig. 1 Bearing capacity equation: q=cNFFF+NFFF+0.5BN F F F Shape factors by De Depth factors by Hansen (1970) Beer (1970) Inclination factors by Meyerhof (1963) and Hanna and Meyerhof (1981) F₁ = F₁₂ = (1-B 90° Fo=1+(x) LN F =1+(-) tan 6 1+tan F, =1-0.4() F =1+0.4(+) B Før = 1 + 2 tan ø'(1 − sin ø”)² D F₁ = (1-2)² B F₁ =1 Table 4.2 Bearing Capacity Factors NE Na Ny N N N K o(overconsolidate) K o(normally consolidated) √OCR 0 5.14 1.00 0.00 1 5.38 1.09 0.07 2 5.63 1.20 0.15 K = tan² (45-%) 34567 5.90 1.31 0.24 6.19 1.43 0.34 6.49 1.57 0.45 21 6.81 1.72 0.57 7.16 1.88 0.71 K₁ = cosa-√cos a-cos² ' =COS& K, cosa + √cos² a-cos² o' 8 7.53 2.06 0.86 =COS& 9 7.92 2.25 1.03 cosa + √cos² a-cos² ' Cosa – -√cos² cos² a-cos² ' 10 8.35 2.47 1.22 11 8.80 2.71 1.44 27 12 9.28 2.97 1.69 K sin² (B+) 13 sin ẞ sin(ẞ-8)[1+ sin('+5) sin(-a)2 sin(B-8) sin(a+B)" 14 15 345 9.81 3.26 1.97 10.37 3.59 2.29 10.98 3.94 2.65 SERDAR2222222223 16 11.63 4.34 3.06 17 12.34 4.77 3.53 18 13.10 5.26 4.07 19 13.93 5.80 4.68 20 14.83 6.40 5.39 15.82 7.07 6.20 16.88 7.82 7.13 18.05 8.66 8.20 24 19.32 9.60 9.44 25 20.72 10.66 10.88 26 22.25 11.85 12.54 23.94 13.20 14.47 28 25.80 14.72 16.72 29 27.86 16.44 19.34 30 30.14 18.40 22.40 31 32.67 20.63 25.99 (continued) K₁ sin(B-) Table 4.2 Bearing Capacity Factors (Continued) sin ẞ sin(B+)[1- sin('+) sin('+a)₁₂ Vsin(+6) sin(a + ẞ) $' No Na N₁ φ' No N₁₂ Ny 32 35.49 23.18 30.22 42 93.71 85.38 155.55 33 38.64 26.09 35.19 43 105.11 99.02 186.54 34 42.16 29.44 41.06 44 118.37 115.31 224.64 35 46.12 33.30 48.03 45 133.88 134.88 271.76 36 50.59 37.75 56.31 46 152.10 158.51 330.35 37 55.63 42.92 66.19 47 173.64 187.21 403.67 38 61.35 48.93 78.03 48 199.26 222.31 496.01 39 67.87 55.96 92.25 49 229.93 265.51 613.16 40 75.31 64.20 109.41 50 266.89 319.07 762.89 41 83.86 73.90 130.22

6. An anchored sheet pile wall is driven in clay. The soil profile and water table are shown in the following figure. The thickness of sand is 10 m, and its properties are ' = 30° y = 16.5 kN/m³, Ysat = 18.5 kN/m³. The properties of clay are C₁ = 45 kN/m², Ysat = 19.0 kN/m³. The surcharge on the surface is 200 kN/m². (1) Determine the theoretical depth of the sheet pile wall by using free earth support method. (2) Calculate the anchor force per unit length of the wall. q = 200 kN/m² Equations and Tables: K. 1-sino' K₁ = 0.95-sin ' 2 m Anchor Y = 16.5 kN/m³ 4 m Sand Water table '=30° Sand Ysat 18.5 kN/m³ 6 m 2' = 30° D Ysat 19.0 kN/m³ Clay C = 45 kN/m² Fig. 1 Bearing capacity equation: q=cNFFF+NFFF+0.5BN F F F Shape factors by De Depth factors by Hansen (1970) Beer (1970) Inclination factors by Meyerhof (1963) and Hanna and Meyerhof (1981) F₁ = F₁₂ = (1-B 90° Fo=1+(x) LN F =1+(-) tan 6 1+tan F, =1-0.4() F =1+0.4(+) B Før = 1 + 2 tan ø'(1 − sin ø”)² D F₁ = (1-2)² B F₁ =1 Table 4.2 Bearing Capacity Factors NE Na Ny N N N K o(overconsolidate) K o(normally consolidated) √OCR 0 5.14 1.00 0.00 1 5.38 1.09 0.07 2 5.63 1.20 0.15 K = tan² (45-%) 34567 5.90 1.31 0.24 6.19 1.43 0.34 6.49 1.57 0.45 21 6.81 1.72 0.57 7.16 1.88 0.71 K₁ = cosa-√cos a-cos² ' =COS& K, cosa + √cos² a-cos² o' 8 7.53 2.06 0.86 =COS& 9 7.92 2.25 1.03 cosa + √cos² a-cos² ' Cosa – -√cos² cos² a-cos² ' 10 8.35 2.47 1.22 11 8.80 2.71 1.44 27 12 9.28 2.97 1.69 K sin² (B+) 13 sin ẞ sin(ẞ-8)[1+ sin('+5) sin(-a)2 sin(B-8) sin(a+B)" 14 15 345 9.81 3.26 1.97 10.37 3.59 2.29 10.98 3.94 2.65 SERDAR2222222223 16 11.63 4.34 3.06 17 12.34 4.77 3.53 18 13.10 5.26 4.07 19 13.93 5.80 4.68 20 14.83 6.40 5.39 15.82 7.07 6.20 16.88 7.82 7.13 18.05 8.66 8.20 24 19.32 9.60 9.44 25 20.72 10.66 10.88 26 22.25 11.85 12.54 23.94 13.20 14.47 28 25.80 14.72 16.72 29 27.86 16.44 19.34 30 30.14 18.40 22.40 31 32.67 20.63 25.99 (continued) K₁ sin(B-) Table 4.2 Bearing Capacity Factors (Continued) sin ẞ sin(B+)[1- sin('+) sin('+a)₁₂ Vsin(+6) sin(a + ẞ) $' No Na N₁ φ' No N₁₂ Ny 32 35.49 23.18 30.22 42 93.71 85.38 155.55 33 38.64 26.09 35.19 43 105.11 99.02 186.54 34 42.16 29.44 41.06 44 118.37 115.31 224.64 35 46.12 33.30 48.03 45 133.88 134.88 271.76 36 50.59 37.75 56.31 46 152.10 158.51 330.35 37 55.63 42.92 66.19 47 173.64 187.21 403.67 38 61.35 48.93 78.03 48 199.26 222.31 496.01 39 67.87 55.96 92.25 49 229.93 265.51 613.16 40 75.31 64.20 109.41 50 266.89 319.07 762.89 41 83.86 73.90 130.22

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter9: Settlement Of Shallow Foundations

Section: Chapter Questions

Problem 9.6P

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Transcribed Image Text:6. An anchored sheet pile wall is driven in clay. The soil profile and water table are shown in the following figure. The thickness of sand is 10 m, and its properties are ' = 30° y = 16.5 kN/m³, Ysat = 18.5 kN/m³. The properties of clay are C₁ = 45 kN/m², Ysat = 19.0 kN/m³. The surcharge on the surface is 200 kN/m². (1) Determine the theoretical depth of the sheet pile wall by using free earth support method. (2) Calculate the anchor force per unit length of the wall. q = 200 kN/m² Equations and Tables: K. 1-sino' K₁ = 0.95-sin ' 2 m Anchor Y = 16.5 kN/m³ 4 m Sand Water table '=30° Sand Ysat 18.5 kN/m³ 6 m 2' = 30° D Ysat 19.0 kN/m³ Clay C = 45 kN/m² Fig. 1 Bearing capacity equation: q=cNFFF+NFFF+0.5BN F F F Shape factors by De Depth factors by Hansen (1970) Beer (1970) Inclination factors by Meyerhof (1963) and Hanna and Meyerhof (1981) F₁ = F₁₂ = (1-B 90° Fo=1+(x) LN F =1+(-) tan 6 1+tan F, =1-0.4() F =1+0.4(+) B Før = 1 + 2 tan ø'(1 − sin ø”)² D F₁ = (1-2)² B F₁ =1 Table 4.2 Bearing Capacity Factors NE Na Ny N N N K o(overconsolidate) K o(normally consolidated) √OCR 0 5.14 1.00 0.00 1 5.38 1.09 0.07 2 5.63 1.20 0.15 K = tan² (45-%) 34567 5.90 1.31 0.24 6.19 1.43 0.34 6.49 1.57 0.45 21 6.81 1.72 0.57 7.16 1.88 0.71 K₁ = cosa-√cos a-cos² ' =COS& K, cosa + √cos² a-cos² o' 8 7.53 2.06 0.86 =COS& 9 7.92 2.25 1.03 cosa + √cos² a-cos² ' Cosa – -√cos² cos² a-cos² ' 10 8.35 2.47 1.22 11 8.80 2.71 1.44 27 12 9.28 2.97 1.69 K sin² (B+) 13 sin ẞ sin(ẞ-8)[1+ sin('+5) sin(-a)2 sin(B-8) sin(a+B)" 14 15 345 9.81 3.26 1.97 10.37 3.59 2.29 10.98 3.94 2.65 SERDAR2222222223 16 11.63 4.34 3.06 17 12.34 4.77 3.53 18 13.10 5.26 4.07 19 13.93 5.80 4.68 20 14.83 6.40 5.39 15.82 7.07 6.20 16.88 7.82 7.13 18.05 8.66 8.20 24 19.32 9.60 9.44 25 20.72 10.66 10.88 26 22.25 11.85 12.54 23.94 13.20 14.47 28 25.80 14.72 16.72 29 27.86 16.44 19.34 30 30.14 18.40 22.40 31 32.67 20.63 25.99 (continued) K₁ sin(B-) Table 4.2 Bearing Capacity Factors (Continued) sin ẞ sin(B+)[1- sin('+) sin('+a)₁₂ Vsin(+6) sin(a + ẞ) $' No Na N₁ φ' No N₁₂ Ny 32 35.49 23.18 30.22 42 93.71 85.38 155.55 33 38.64 26.09 35.19 43 105.11 99.02 186.54 34 42.16 29.44 41.06 44 118.37 115.31 224.64 35 46.12 33.30 48.03 45 133.88 134.88 271.76 36 50.59 37.75 56.31 46 152.10 158.51 330.35 37 55.63 42.92 66.19 47 173.64 187.21 403.67 38 61.35 48.93 78.03 48 199.26 222.31 496.01 39 67.87 55.96 92.25 49 229.93 265.51 613.16 40 75.31 64.20 109.41 50 266.89 319.07 762.89 41 83.86 73.90 130.22

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