6. AlCl3 reacts with K4[Fe(CN)6] to produce A14[Fe(CN)6]3 according to the equation 4 AlCl3 (aq) + 3 K4[Fe(CN)6] (aq) → Al4[Fe(CN)6]3 (s) + 12 KCl (aq) (a) Which reactant is limiting if 1.704 g of AlCl3 and 2.327 g of K4[Fe(CN)6] are allowed to react? (b) What mass of A14[Fe(CN)6]3 can be produced? (c) What mass of the excess reactant remains when the reaction is complete? Formula weights (g/mol): AlCl3 133.3396 K4[Fe(CN)6] 368.3464 Al4[Fe(CN)6]3 743.79
6. AlCl3 reacts with K4[Fe(CN)6] to produce A14[Fe(CN)6]3 according to the equation 4 AlCl3 (aq) + 3 K4[Fe(CN)6] (aq) → Al4[Fe(CN)6]3 (s) + 12 KCl (aq) (a) Which reactant is limiting if 1.704 g of AlCl3 and 2.327 g of K4[Fe(CN)6] are allowed to react? (b) What mass of A14[Fe(CN)6]3 can be produced? (c) What mass of the excess reactant remains when the reaction is complete? Formula weights (g/mol): AlCl3 133.3396 K4[Fe(CN)6] 368.3464 Al4[Fe(CN)6]3 743.79
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![6.
AlCl3 reacts with K4[Fe(CN)6] to produce A14[Fe(CN)6]3 according to the equation
4 AlCl3 (aq) + 3 K4[Fe(CN)6] (aq) → Al4[Fe(CN)6]3 (s) + 12 KCl (aq)
(a) Which reactant is limiting if 1.704 g of AlCl3 and 2.327 g of K4[Fe(CN)6] are allowed to react?
(b) What mass of A14[Fe(CN)6]3 can be produced?
(c) What mass of the excess reactant remains when the reaction is complete?
Formula weights (g/mol): AlCl3 133.3396 K4[Fe(CN)6] 368.3464
Al4[Fe(CN)6]3 743.79](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4de49249-bdf1-40d3-b1d2-0024b6daad41%2F5f90a893-d041-48c1-a525-dc9aa5ef69a9%2Fz1qsrwq_processed.png&w=3840&q=75)
Transcribed Image Text:6.
AlCl3 reacts with K4[Fe(CN)6] to produce A14[Fe(CN)6]3 according to the equation
4 AlCl3 (aq) + 3 K4[Fe(CN)6] (aq) → Al4[Fe(CN)6]3 (s) + 12 KCl (aq)
(a) Which reactant is limiting if 1.704 g of AlCl3 and 2.327 g of K4[Fe(CN)6] are allowed to react?
(b) What mass of A14[Fe(CN)6]3 can be produced?
(c) What mass of the excess reactant remains when the reaction is complete?
Formula weights (g/mol): AlCl3 133.3396 K4[Fe(CN)6] 368.3464
Al4[Fe(CN)6]3 743.79
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