6. A source of vibration begins abruptly and is represented by the equation: X1 5.2 e jot-0.5) Time delay where the phase is given in radians. A second source of vibration of the same frequency as the first, begins 5ms after the first and is twice as loud. Write down the equation for this second vibration, x2 in the same form as x₁ if both vibrations have a frequency of 55Hz.
6. A source of vibration begins abruptly and is represented by the equation: X1 5.2 e jot-0.5) Time delay where the phase is given in radians. A second source of vibration of the same frequency as the first, begins 5ms after the first and is twice as loud. Write down the equation for this second vibration, x2 in the same form as x₁ if both vibrations have a frequency of 55Hz.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
Break down how got the answer simply? For period what is as?

Transcribed Image Text:5. A mechanical oscillator with a quality factor of 2 comprises a mass of 50 g attached
to a spring of stiffness 3250 N/m. When the mass is subject to an oscillating driving
force of magnitude 20 N, the resultant frequency of oscillation of the system is 50 Hz.
a). Calculate the value of the mechanical resistance, Rm, for the system.
b). What percentage of the maximum power is dissipated in the system when is it
driven to oscillate at 50 Hz?
c). State whether the system is underdamped, critically damped or overdamped when
the driving force is turned off and justify your answer.
6. A source of vibration begins abruptly and is represented by the equation:
X1 5.2 e j(oot - 0.5)
where the phase is given in radians.
A second source of vibration of the same frequency as the first, begins 5ms after the
first and is twice as loud. Write down the equation for this second vibration, x2 in the
same form as x₁ if both vibrations have a frequency of 55Hz.
Time delay
D.Moran

Transcribed Image Text:3)x
Cine
ni
D
f
ime
H
Perial of 1 oscillation T=4 = 55
0.018s
X = S.Z
= SSH₂ For XlXz
³
Wt-0.5)
evence
So phare differen.
(radians)
Phase of
Sms (0.005s)
=
between xlx ₂
=
between X, IX₂
0.005
0.018
1.35
X2T
D
radians
1.75 + (0.5)
1.25
radians
is twice X₁ je. 2X5.2=10
Amplitude of X₂
So, x ₂ = 10.4 + +1.25)
x₂ =
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