Ch. 6 # 6 . Please see attached image for Physics question . Thank you . **Problem 6:** A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 22.0 m. She pushes in a direction 29.0° below the horizontal. A 48.0-N frictional force opposes the motion of the cart. **Questions:**- (a) What is the magnitude of the force that the shopper exerts?- Determine the work done by: - (b) the pushing force, - (c) the frictional force, and - (d) the gravitational force.*Note: There are no graphs or diagrams provided in the image.*

Name: Ch. 6 # 6 . Please see attached image for Physics question . Thank you
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Description: Ch. 6 # 6 . Please see attached image for Physics question . Thank you . **Problem 6:** A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 22.0 m. She pushes in a direction 29.0° below the horizontal. A 48.0-N frictional

Answered: 6. A person pushes a 16.0-kg shopping…

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Ch. 6 # 6 . Please see attached image for Physics question . Thank you .

**Problem 6:** A person pushes a 16.0-kg shopping cart at a constant velocity for a distance of 22.0 m. She pushes in a direction 29.0° below the horizontal. A 48.0-N frictional force opposes the motion of the cart.

**Questions:**
- (a) What is the magnitude of the force that the shopper exerts?
- Determine the work done by:
- (b) the pushing force,
- (c) the frictional force, and
- (d) the gravitational force.

*Note: There are no graphs or diagrams provided in the image.*

Expert Solution

Step 1

For the cart to travel at a constant velocity, the horizontal force applied by the person should be equal in magnitude to the frictional force opposing the cart. In this scenario, the net force becomes zero and the acceleration will be zero leading to constant velocity.

Part a)

The frictional force $F_{f} = 48 N$

Let the force applied by the person is P.

Equating the horizontal forces,

$P \cos θ = F_{f}$

$P \times \cos 29^{o} = 48$

$P = 54.88 N$

Therefore, the magnitude of the force the shopper exerts is 54.88 N.

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