6. A corrupt bartender attempts to prepare a 100.00 cm³ of some drink by mixing 30.0 cm³ of ethanol with 70 cm³ of water at 25 °C. Does he succeed? If not, what volumes should have been mixed in order to arrive at a mixture of the same strength, but of the required volume? VM(H₂O) = 18.0 cm³/mol. (at composition) | M (H₂O) = 18.02 g/mol. | p = 0.997 g/cm³ ▼¹ (C₂H²O) = 53.6 cm³/mol. (at composition) | M (C₂H²O)] = 46 g/mol. | p = 0.79 g/cm³
6. A corrupt bartender attempts to prepare a 100.00 cm³ of some drink by mixing 30.0 cm³ of ethanol with 70 cm³ of water at 25 °C. Does he succeed? If not, what volumes should have been mixed in order to arrive at a mixture of the same strength, but of the required volume? VM(H₂O) = 18.0 cm³/mol. (at composition) | M (H₂O) = 18.02 g/mol. | p = 0.997 g/cm³ ▼¹ (C₂H²O) = 53.6 cm³/mol. (at composition) | M (C₂H²O)] = 46 g/mol. | p = 0.79 g/cm³
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![6. A corrupt bartender attempts to prepare a 100.00 cm³ of some drink by mixing 30.0 cm³ of
ethanol with 70 cm³ of water at 25 °C. Does he succeed? If not, what volumes should have
been mixed in order to arrive at a mixture of the same strength, but of the required
volume?
-M
(H₂O) = 18.0 cm³/mol. (at composition) | M (H₂O) = 18.02 g/mol. | p = 0.997 g/cm³
V (C₂H₂O) = 53.6 cm³/mol. (at composition) | M (C₂HO)] = 46 g/mol. | p = 0.79 g/cm³
-M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fca6b5de9-d666-4be4-bec5-372f49facd74%2Febcd5c86-1ffd-4215-8a1f-03755a46e022%2Fbph5dxd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:6. A corrupt bartender attempts to prepare a 100.00 cm³ of some drink by mixing 30.0 cm³ of
ethanol with 70 cm³ of water at 25 °C. Does he succeed? If not, what volumes should have
been mixed in order to arrive at a mixture of the same strength, but of the required
volume?
-M
(H₂O) = 18.0 cm³/mol. (at composition) | M (H₂O) = 18.02 g/mol. | p = 0.997 g/cm³
V (C₂H₂O) = 53.6 cm³/mol. (at composition) | M (C₂HO)] = 46 g/mol. | p = 0.79 g/cm³
-M
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