What is the change of energy (L. atm) of a system that absorbed 18.8 L atm of heat and had its volume changed from 2.2 L to 15.8 L against a pressure of 1.5 atm? O AE = 18.8 + [1.5(15.8 + 2.2) %3D O AE= -18.8+ (1.5(15.8- 2.2)] O AE = -18.8 +[-1.5(15.8- 2.2)1 O AE = 18.8 +[- 1.5(15.8- 2.2)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
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Chapter1: Introduction
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What is the change of energy (L. atm) of a system that absorbed 18.8 L atm of heat and had its
volume changed from 2.2 L to 15.8L against a pressure of 1.5 atm?
O AE = 18.8 + [1.5(15.8 + 2.2)
O AE = -18.8+[1.5(15.8- 2.2)]
%3D
O AE = -18.8 + [-1.5(15.8 - 2.2)
AE = 18.8 +- 1.5(15.8-2.2)
Transcribed Image Text:What is the change of energy (L. atm) of a system that absorbed 18.8 L atm of heat and had its volume changed from 2.2 L to 15.8L against a pressure of 1.5 atm? O AE = 18.8 + [1.5(15.8 + 2.2) O AE = -18.8+[1.5(15.8- 2.2)] %3D O AE = -18.8 + [-1.5(15.8 - 2.2) AE = 18.8 +- 1.5(15.8-2.2)
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