6 in.- 6 in.- Probs. 8–71/72

Q: Two circular shafts are joined together between fixed supports to resist a torsional moment of 80…

A: Given SteelHollow circularDo=100mmDi=80mmG=150GPa AluminiumSolid circularD=75mmG=70GPa To find The…

Q: The five-bolt connection must support an applied load of P = 149 kips. If the average shear stress…

A:

Q: The steel shafts are connected together using a fillet weld as shown in the figure below. (Figure 1)…

A: Applied Torque= 63 N-m  Critical section is along a-a

Q: 3

A: Given:- factor of safety =1.6 force=100kips To find:- most economical option

Q: A tubular aluminum alloy [G= 4,000 ksi] shaft is being designed to transmit 480 hp at 2,700 rpm. The…

A: Given values: Power, P = 480 HP Speed, N = 2700 rpm G = 4000 ksi = 576000 kip/ft2 Maximum shear…

Q: A torsion member is fabricated fror concentric thin tubes. At the ends, the are welded to rigid…

A: Given data: Inner radius = r outer radius = 2r shear stress in outer tube = τ

Q: A flanged bolt coupling consists of ten 16-mm-diameter bolts spaced evenly around a bolt circle 650…

A: Given data,    No of bolts = 10 Diameter of bolt (d) = 16 mm Diameter of bolt circle = 0.650 m…

Q: 3/4 130 mm O O O 25 mm 25 mm

A: Fbd is shown below Upper plate , bolt and lower plate fbd  Bolt is being cut by one plane as they…

Q: If a horizontal force of P = 100 N is applied perpendicular to the handle of the lever at A,…

A: FBD of the given problem:

Q: (1) A L1 B (2) L2 C L3 (3) D

A:

Q: P1.020 For the clevis connection shown in the figure, determine the maximum applied load P that can…

A: d = 15 mm  = 75 MPa

Q: u = -c(y² + væ), v = 2cxy |

A: Given:- u=-c(y2+vx) v=2cxy c=constant v=Poisson's Ratio To find:- stresses

Q: A bracket has been loaded as shown in figure. Compute the top and bottom fibre stress at section…

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Q: For the shaft loaded as shown, which point(s) at the section shown experiences the maximum shear…

A: Let's draw the FBD  for first figure At the L shaft observe the stresses and their directions…

Q: iven: -The members are a semi circular cross section with a radius of 16mm -Thickness of each…

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Q: Solve the plate shown in the figure, Include fbd on solutions

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Q: Two square rods AB and BC are welded together at B and loaded as shown. Determine the average normal…

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Q: Q.1//The bar AD is considered to be absolutely rigid and is horizontal before the load of 200 KN is…

A: to find stress in each rod

Q: P 100 mm 10 mm 10 mm P

A: As per bartleby guidelines the given data closely related to the IS code provisions also the term…

Q: A composite shaft arrangement of brass and steel is shown below. The allowable shear stress are 100…

A: A composite shaft made of brass and steel.The diameter of the steel part is 80 mm.The diameter of…

Q: The safety stress for the steel bar shown in the figure is  ϭallow= 160MPa. According to the…

A: Solution:

Q: The figure below shows a shaft of three segments. It is restrained (fixed support) at both sides and…

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Q: The steel shafts are connected together using a fillet weld as shown in the figure below. (Figure 1)…

A: T = 63 N. m

Q: two steel plates are bolted to the wooden beam shown by 30-mm-diameter bolts spaced at 200 mm.…

A: Find modular ratio:n=EwEs=40200=15so,Reduced width of wood =1505=30mmFInd…

Q: s to be made of steel having an ultimate shearing stress of 400 MPa, determine: (a.)The diameter of…

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Q: The C83400-red-brass rod AB and 2014-T6-aluminum rod BC are joined at the collar B and fixed…

A: Given Data : Cross sectional area of each section = 1.75 in2 To Find :

Q: The outer diameter of the bronze pipe flush-mounted at the A and B points is given as D and the wall…

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Q: The aluminum rod AB (Gal = 27 GPa) is bonded to the brass rod BD (Gbr = 39 GPa). The portion CD of…

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Q: For the lap joint below, the maximum safe load P if the shearing stress in the rivets, (diameter of…

A: This question is related to the Bolt connection from Steel design

Q: Question 2 300 mm 20 mm -200 mm- ta 200 mm Section a-a 20 mm The maximum allowable tensile strength…

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Q: A compound shaft consists of brass segment (1) and aluminum segment (2). Segment (1) is a solid…

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Q: Determine maximum load (P1) that can be applied without exceeding design tensile stress in plates

A: Solution: allowable tensile stress F1 = 0.6 Fy     = 0.6 x 248 = 149 Mpa P = FtAn An =…

Q: The lap joint is connected together using a 32 mm diameter bolt. Determine the permanent shear…

A: Given data in question Load 750 kN Diameter 32 mm To find out  Permenant strain

Q: Two plates with a thickness of 35mm, width of 160mm, and length of 200mm are joined ogether by a pin…

A: thickness =35mm Width =160mm Length =200mm Pin Diameter =60mm

Q: Two circular shafts are joined together between fixed supports to resist a torsional moment of 80…

A:

Q: A bolted connection s

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Q: -1000 mm- Weid P -500- 175 1 75 25- 200 150 mm 25 -||-|- 25

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Q: Determine the principal stresses. Show all results on complete sketches of differential elements.…

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Q: The assembly consists of two posts AD and CF made of steel and having cross- sectional area of 1000…

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Q: Hanger Rod Bolt Top Yoke- Bottom Strap FIGURE 2

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Q: A flanged bolt coupling consists of six - ½ inch steel bolts evenly spaced around a bolt circle of…

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Q: If the clamping force at G is 900 N, determine the horizontal force F that must be applied…

A: Given ;

Q: The flange and web plates of the doubly symmetric built-up section are connected by continuous 10 mm…

A:

Q: The strain at point A on the bracket has components = 330 (10-), ey = 560 (10-). Yxy = -570 (10-0).e…

A: Data given εx = 330×10-6 εy = 560×10-6 εz = 0 γxy = 570×10-6 To find:- Maximum shear strain…

Q: Shaft AB and DC are connected by gears. A torque of 35 Nm is applied at end D of shaft CD. While…

A: Given data as,                       G=80 GPaTDC=35 N-mm =35×103N-mm\Tallowable=50MPaangle of…

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.