6 Find out the smallest value of load RL in the amplifier circuit shown in fig so thatthe voltage gain is at least 40. The dynamic emitter resistance of the transistor is25 0. The coupling and by-pass capacitors may be assumed short at signalfrequency.+12kRc3k8kRL4k4kRE

Given : In the given question they have mentioned a NPN transistor circuit. For the given common…

Answered: 6 Find out the smallest value of load…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

Vcc-+15V RC1 RC2 5 k2 5 ka Vout Vo2 RB1 1 ka RB2 1 ka Q2 Vs2 Vs1 RE 7.5 ka VEE-15V Assume Ql and Q2 are identical transistors with B=hfec=100 and VBE-0.7V. Determine hiej and hiez. Determine the differential gains Ad, (for single-ended) and Ada (for double ended). Determine the common-mode gains Ac, (for single-ended) and Aca (for double ended). Determine the common-mode rejection ratio CMRR for single-ended output. Determine the common-mode rejection ratio CMRR for double-ended output.
1:- For the emitter bias circuit shown in figure(1), if Vec-20V, B-50, RC-2k2, RB-430k2, and RE=1kQ. Vee (a) Determine IB, IC, and IE. (b) Determine VCE, VC, VE, VB. RB (c) Draw the de load line. Vo (d) The stability factor SICO. vì For the amplifier
Q4 : The input impedance of a JFET transistor is so high, state the reason .
A common emitter amplifier has a 15V power supply. If we design for a 6.5V swing (peak voltage) at the output voltage what will the DC voltage drop be across RE? Group of answer choices 2V 10V 6.5 5V
For a common-collector amplifier, RE = 100N, r. = 10N, and 30ac = 150. If a 10 mV signal is applied to the base , the output signal is approximately 10 mV 150 mV 1.5 V 100 mV
Given the four statements below, which off the following statements are true about power amplifiers? i. In a Class A amplifier the output transistors are always on while in Class C amplifier, one output transistor turns on every half cycle only. ii. Class C amplifier have large amount of signal distortion than class A amplifier. iii. Class C amplifier have high power efficiency than class A amplifier. iv. The position of the quiescent point for class C is below the x-axis while clas A amplifier is exactly in the x-axis.
10-when the emitter resistance RE doubles the ac emitter resistance a-Increases. b-decreases. c-Remains the same. d-Cannot be determined. 11-To reduce the distortion in a CE amplifier, reduce the a-DC emitter current. b-Base-emitter voltage. c-Collector current. d-AC base voltage. 12-The output voltage of a CE amplifier is a-Amplified. b-Inverted. c-180° out of phase with the input. d-All of the above.
Question-2: For the amplifier shown, determine: 1. Maximum value for the emitter bypass capacitor, C2, if the amplifier must operate over a frequency range from 200 Hz to 10 kHz. Vcc +10 V Boc-100 Bac=175 2. Voltage gain Ay. Re 4.7 kfl R C, 47 Vout 3. The DC collector voltage Vc. Vin 4. The Attenuation. R 47 kfN 5. The AC collector voltage Ve. R, 600 n R2 10 kN R 470 1 Vs 15 mv 470 1
Q.2/ For the amplifier's circuits shown below: a. Determine the Q-point for each amplifier circuit. b. What is the maximum peak value of collector current that can be realized in each circuit? c. What is the maximum peak value of output voltage in each circuit? +12 V +12 V RC C3 RC C3 R1 6802 R 12 k 100 N Vout 470 2 Vut 10 μ 10 μF V RL 1002 10 μF 10 µF REi 4.7 N REI 22 Ω2 R2 510 n RE2 75 0 C2 10 uF R2 4.7 kN RE2 120 N C2 RL 10 uF 470 N (a) Be = Bpc = 125 (b) Bac = BDc = 120
solve
some one solved it but, I think there is a mistake. can you please just solve number 4 and 5
Kindly choose the best and appropriate answer.

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6 Find out the smallest value of load RL in the amplifier circuit shown in fig so that the voltage gain is at least 40. The dynamic emitter resistance of the transistor is 25 n. The coupling and by-pass capacitors may be assumed short at signal frequency. +12k Rc 3k 8k RL 4k 4k RE