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(6) A clockwise moment M= 150 lb-ft is applied at the center C of the 60 lb uniform sphere that is supported by a rough inclined wall A and a smooth vertical wall B as shown. The radius of the sphere is 5 ft. If the sphere does not slip and remains in equilibrium, determine the normal force from wall B and the normal and friction forces from wall A. Ans: NB = 69.3 lb, N₁ = 86.6 lb, F₁ = 30 lb M 30° A B °C

(6) A clockwise moment M= 150 lb-ft is applied at the center C of the 60 lb uniform sphere that is supported by a rough inclined wall A and a smooth vertical wall B as shown. The radius of the sphere is 5 ft. If the sphere does not slip and remains in equilibrium, determine the normal force from wall B and the normal and friction forces from wall A. Ans: NB = 69.3 lb, N₁ = 86.6 lb, F₁ = 30 lb M 30° A B °C

Trigonometry (MindTap Course List)
Trigonometry (MindTap Course List)
10th Edition
ISBN:9781337278461
Author:Ron Larson
Publisher:Ron Larson
Chapter3: Additional Topics In Trigonometry
Section: Chapter Questions
Problem 43CT
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(6) A clockwise moment M= 150 lb-ft is applied at the center C of the 60 lb uniform sphere that is supported by a rough inclined wall A and a smooth vertical wall B as shown. The radius of the sphere is 5 ft. If the sphere does not slip and remains in equilibrium, determine the normal force from wall B and the normal and friction forces from wall A. Ans: NB = 69.3 lb, N₁ = 86.6 lb, F₁ = 30 lb M 30° A B °C
Transcribed Image Text:(6) A clockwise moment M= 150 lb-ft is applied at the center C of the 60 lb uniform sphere that is supported by a rough inclined wall A and a smooth vertical wall B as shown. The radius of the sphere is 5 ft. If the sphere does not slip and remains in equilibrium, determine the normal force from wall B and the normal and friction forces from wall A. Ans: NB = 69.3 lb, N₁ = 86.6 lb, F₁ = 30 lb M 30° A B °C
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