A 68 kg skydiver jumps out of an airplane. We assume that the forces acting on the body are the force of gravity and a retarding force of air resistance with direction opposite to the direction of motion and with magnitude cv² where c = 0.1759 and v(t) is the velocity of the skydiver at time t (and upward is positive velocity). The gravitational constant is g = 9.8m/s². a) Find a differential equation for the velocity v: dv dt b) Determine the terminal velocity in meters per second for free-fall (no parachute). terminal velocity = Note: Answer should be negative for downward velocity. m/s

Advanced Engineering Mathematics
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Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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A 68 kg skydiver jumps out of an airplane. We assume that the forces acting on the body are the force of gravity and a retarding force of air resistance
with direction opposite to the direction of motion and with magnitude cv² where c = 0.175 kg and v(t) is the velocity of the skydiver at time t (and
upward is positive velocity). The gravitational constant is g = 9.8m/s².
m
a) Find a differential equation for the velocity v :
dv
dt
b) Determine the terminal velocity in meters per second for free-fall (no parachute).
terminal velocity= m/s
Note: Answer should be negative for downward velocity.
Transcribed Image Text:A 68 kg skydiver jumps out of an airplane. We assume that the forces acting on the body are the force of gravity and a retarding force of air resistance with direction opposite to the direction of motion and with magnitude cv² where c = 0.175 kg and v(t) is the velocity of the skydiver at time t (and upward is positive velocity). The gravitational constant is g = 9.8m/s². m a) Find a differential equation for the velocity v : dv dt b) Determine the terminal velocity in meters per second for free-fall (no parachute). terminal velocity= m/s Note: Answer should be negative for downward velocity.
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