(4) Determine (a) the force component perpendicular to line OAand (b) then calculate the moment produced by the 4 lb forceabout point O.Ans: (a) 3.06 lb (b) Mo=24.5 lb-in CCWF=4 lb10°30°

Answered: Image /qna-images/answer/7d86b2c5-2037-4825-9323-62aeed9573a0.jpg

Answered: (4) Determine (a) the force component…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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(1) Determine the two components Fa and Fb of the 4 kN force along the oblique a- and b-axes. Also determine the two projections Pa and Pb of the 4 kN force onto both a- and b-axes. Ans: Fa 1.935 kN, Fb = 2.39 kN, Pa = 3.63 kN, Pb = 3.76 kN 15° 40° F= 4 kN x
#4
(3) The gusset plate is subjected to two forces F₁ = 0.8 KN and F2 = 0.9 kN at point A as shown. If they are replaced with Fa and Fb and the resultant forces from the two pairs are identical, determine the magnitudes of Fa and Fb. Ans: Fa=1.199 kN, Fb = 0.433 kN F₂ 30°-40° x
(2) For the two oblique axes shown, determine the component of F along the b-axis F, if the projection of force F onto the a-axis is Pa = 250 N. Ans: Fb = 612 N 60° 45°
(5) The force F=80 N is applied to the crank OA through rod AB at point A as shown, with OA= 0.05 m, 0 = 55°, and ẞ= 15°. (a) Determine from geometry the moment arm d for the force about point O, and then (b) determine the moment of the force F about point O. Ans: (a) 0.0383 m (b) 3.06 N·m CCW F B
(5) The 16 N force is applied to the foot valve AC at point A as shown with a = 28°. Determine (a) the force component perpendicular to line BA and (b) then calculate the moment produced by the force about point B. Ans: (a) 7.51 N (b) MB = 1.277 N·m CCW 20° 16 N 170 mm 80 mm
(8) Replace the two forces and a couple acting on the beam by an equivalent resultant force Ŕ and resultant moment MA at point A. Ans: R=1.644 +1.159 kN, M₁ = 2.22 kNm CCW A 2 kN 0.5 m 1.5 m 70° 0.15 m 0.15 m 500 N·m -x 1.2 kN

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(4) Determine (a) the force component perpendicular to line OA and (b) then calculate the moment produced by the 4 lb force about point O. Ans: (a) 3.06 lb (b) Mo=24.5 lb-in CCW F=4 lb 10° 30°