Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
9
![**Problem 9:**
A mom pulled a stroller 150 meters by a force of 60 Newtons, applied at an angle of 30° to the road. Find the work done.
*(Answer: 3)*
---
**Explanation:**
To solve this problem, we need to calculate the work done using the formula:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
Where:
- Force = 60 N
- Distance = 150 m
- \(\theta\) = 30°
The cosine of 30° is \(\sqrt{3}/2\). Therefore:
\[
\text{Work} = 60 \times 150 \times \cos(30°) = 60 \times 150 \times \frac{\sqrt{3}}{2}
\]
Calculate the actual numerical result to find the work done.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78f85931-ed68-43c6-82f9-075f499bfced%2F2fc43663-148f-4164-8cfc-fd0b50edd302%2Fmrjwllp_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem 9:**
A mom pulled a stroller 150 meters by a force of 60 Newtons, applied at an angle of 30° to the road. Find the work done.
*(Answer: 3)*
---
**Explanation:**
To solve this problem, we need to calculate the work done using the formula:
\[
\text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta)
\]
Where:
- Force = 60 N
- Distance = 150 m
- \(\theta\) = 30°
The cosine of 30° is \(\sqrt{3}/2\). Therefore:
\[
\text{Work} = 60 \times 150 \times \cos(30°) = 60 \times 150 \times \frac{\sqrt{3}}{2}
\]
Calculate the actual numerical result to find the work done.
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