6 5 F1: 90.264 EX: c:\eft\H1\ZG.ppg =0 4.171 4.090 CH3-C-O-CH2 CH3 Ethyl Acetate 2.00 4 3 2.049 2.95 3.02 2 1 1.345 1.266 SW1: 1578 PW: 11.9 us PD: 3.0 sec OF1: 540.0 NA: 1 PTS1d: 8192 LB: 0.0 1.185 0 600'0 -1 PPM USER: -- DATE: 08/31/24 (15:03) .

(c) 1. THF H2C CEN 7. 2. H30* N(CH312 (d) 1. THF N' 2. H3O* 2016 Cmn Laung

9. r. S. H₂CRO4 A d= & OH NO₂ H₂ Pd/C NO₂ 6 = iq= HNO3 H₂, Pd/C H₂SO4

File Edit View History Bookmarks Profiles Tab Window Help Chrome G Nar x C Nar x C Nar x C Usi x C Cor x b Ans x O Ho X G familia O Ass X A ALE X A www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-Ivdr8RUjiNBZSaKW4JswZj9xS7uMs6c1gBjbNya89Yw OpenCCC: Interna.. O Form N-648 6 New Tab I Downloads P lapd G My Account Apply Now | Join... Los sdd Initial Knowledge Check Question 24 Name the family to which each organic compound belongs. The first answer has been filled in for you. compound family 0=ɔ- HN amide || CH,-C- NH – CH, | | || I Don't Know Submit O 2022 McGraw Hill LLC in_6_dome_1.mov FEB 14 átv MacBook Air 08 F3 F1 000 000 F2 F4 F5 DD F6 110

f) 엿 1- 2- H+ Br 3- Ht, H2O 1-O3, CH2Cl2, -78 °C 2- CH3SCH3 CgH1402

Question 7

A app.edulastic.com/student/assessment/60525b29af74cf0008c2b68f/class/5f20cf3d5dd16ded17965e85/uta/6054999e5 0646a4/itemld/60525b2.. Question 7/19 > NEXT A BOOKMARK Almonds are edible seeds that grow on trees. Wild almonds typically have a bitter taste caused by a chemical in the almond. If an organism eats wild almonds, a chemical reaction occurs that releases the bitter taste. However, a genetic mutation in the almond tree can occur that prevents wild almonds from producing the bitter taste. Which statement describes how this type of mutation could affect these wild almond trees? 7 A This mutation could increase the population of wild almond trees. B This mutation could increase the life span of wild almond trees. (c) This mutation could decrease the rate of the production for wild almond tree P Type here to search DELL

Why is this correct?

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2. The following eight structures are all isomers of C6H14O. Each structure corresponds to one of the predicted ¹H NMR spectra pictured on the next two pages of this document. The integral values for each peak are next to that peak. Indicate which structure matches each spectrum by drawing the structures in the boxes along the right side of the pages. Use the letter codes provided to label the chemically equivalent hydrogens on the structures. One example is provided. Xor A 2H 1H <- A 4H -3₂₂ OH B 2H tot 2 PPM PPM -N 2 PPM N- -~ B 12H DE C 2H 2H 1H B 4H 6H ха по мон F 6H B B B w