6-10. BaCl2 H2O(s) loses water when it is heated in an oven: BaCl2 • H20(s) = = BaCl2(s) + H20(g) AH° = 63.11 kJ/mol at 25°C %3D AS° = +148 J/(K• mol) at 25°C (a) Write the equilibrium constant for this reaction. Calculate the vapor pressure of gaseous H2O (PH,0) above BaCl2 H2O at 298 K. (b) If AH° and AS° are not temperature dependent (a poor assump- tion), estimate the temperature at which PH0 above BaCl, H,O(s) will be 1 bar.

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**Problem 6-10**

BaCl₂·H₂O(s) loses water when it is heated in an oven:

\[ \text{BaCl}_2 \cdot \text{H}_2\text{O(s)} \rightarrow \text{BaCl}_2\text{(s)} + \text{H}_2\text{O(g)} \]

\[
\Delta H^\circ = 63.11 \, \text{kJ/mol at } 25^\circ \text{C}
\]

\[
\Delta S^\circ = +148 \, \text{J/(K} \cdot \text{mol) at } 25^\circ \text{C}
\]

(a) **Write the equilibrium constant for this reaction. Calculate the vapor pressure of gaseous H₂O (\( P_{\text{H}_2\text{O}} \)) above BaCl₂·H₂O at 298 K.**

(b) **If \(\Delta H^\circ\) and \(\Delta S^\circ\) are not temperature dependent (a poor assumption), estimate the temperature at which \( P_{\text{H}_2\text{O}} \) above BaCl₂·H₂O(s) will be 1 bar.**

**Graph/Diagram Explanation:** 

There are no graphs or diagrams in this problem. The question involves thermodynamic calculations related to the equilibrium constant and changes in enthalpy and entropy for a chemical reaction.
Transcribed Image Text:**Problem 6-10** BaCl₂·H₂O(s) loses water when it is heated in an oven: \[ \text{BaCl}_2 \cdot \text{H}_2\text{O(s)} \rightarrow \text{BaCl}_2\text{(s)} + \text{H}_2\text{O(g)} \] \[ \Delta H^\circ = 63.11 \, \text{kJ/mol at } 25^\circ \text{C} \] \[ \Delta S^\circ = +148 \, \text{J/(K} \cdot \text{mol) at } 25^\circ \text{C} \] (a) **Write the equilibrium constant for this reaction. Calculate the vapor pressure of gaseous H₂O (\( P_{\text{H}_2\text{O}} \)) above BaCl₂·H₂O at 298 K.** (b) **If \(\Delta H^\circ\) and \(\Delta S^\circ\) are not temperature dependent (a poor assumption), estimate the temperature at which \( P_{\text{H}_2\text{O}} \) above BaCl₂·H₂O(s) will be 1 bar.** **Graph/Diagram Explanation:** There are no graphs or diagrams in this problem. The question involves thermodynamic calculations related to the equilibrium constant and changes in enthalpy and entropy for a chemical reaction.
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