At a specific temperature, the reaction: 2 H20(g) +2 H2(9) + O2(g) has Keg = 1.40 x 10-4. At the same temperature, determine Keg for the reaction: H2(g) + 1/2 O2(9) → H20(g) » a. 1.40 x 10-4 O b.1.43 x 10-4 C. 7.14 x 10+3 Od. 1.43 x 10+4 e. 84.5
At a specific temperature, the reaction: 2 H20(g) +2 H2(9) + O2(g) has Keg = 1.40 x 10-4. At the same temperature, determine Keg for the reaction: H2(g) + 1/2 O2(9) → H20(g) » a. 1.40 x 10-4 O b.1.43 x 10-4 C. 7.14 x 10+3 Od. 1.43 x 10+4 e. 84.5
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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At a specific temperature, the reaction:
has Keq = 1.40 x 10-4.
At the same temperature, determine Keq for the reaction:
![**Equilibrium Constant Calculation**
At a specific temperature, the reaction:
\[ 2 \, \text{H}_2\text{O}_{(g)} \rightleftharpoons 2 \, \text{H}_2_{(g)} + \text{O}_2_{(g)} \]
has \( K_{eq} = 1.40 \times 10^{-4} \).
At the same temperature, determine \( K_{eq} \) for the reaction:
\[ \text{H}_2_{(g)} + \frac{1}{2} \text{O}_2_{(g)} \rightleftharpoons \text{H}_2\text{O}_{(g)} \]
**Answer Choices:**
- a. \( 1.40 \times 10^{-4} \)
- b. \( 1.43 \times 10^{-4} \)
- c. \( 7.14 \times 10^{3} \)
- d. \( 1.43 \times 10^{4} \)
- e. \( 84.5 \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1dd351b3-52c1-452a-96ee-ed63b06ec483%2F1c97414d-40e3-4bd9-9c4f-45841bc28c6e%2Fq83iqs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Equilibrium Constant Calculation**
At a specific temperature, the reaction:
\[ 2 \, \text{H}_2\text{O}_{(g)} \rightleftharpoons 2 \, \text{H}_2_{(g)} + \text{O}_2_{(g)} \]
has \( K_{eq} = 1.40 \times 10^{-4} \).
At the same temperature, determine \( K_{eq} \) for the reaction:
\[ \text{H}_2_{(g)} + \frac{1}{2} \text{O}_2_{(g)} \rightleftharpoons \text{H}_2\text{O}_{(g)} \]
**Answer Choices:**
- a. \( 1.40 \times 10^{-4} \)
- b. \( 1.43 \times 10^{-4} \)
- c. \( 7.14 \times 10^{3} \)
- d. \( 1.43 \times 10^{4} \)
- e. \( 84.5 \)
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