54. Consider the jointly discrete random variables from homework questions 54-57 with joint pmf: f(x, y) = P(X= x, Y = y) = X = 0 = 01/45 1 2 6/45 3/45 1 10/45 15/450 2 10/45 0 0 (a) Find the covariance of X and Y. (b) Find the correlation between X and Y.

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64. Consider the jointly discrete random variables from homework questions 54-57 with joint pmf:
f(x, y) = P(X = x, Y = y) =
Y =
X =
0
1
2
1/45 6/45 3/45
0
1
10/45 15/45 0
2 10/45 0
0
(a) Find the covariance of X and Y.
(b) Find the correlation between X and Y.
Transcribed Image Text:64. Consider the jointly discrete random variables from homework questions 54-57 with joint pmf: f(x, y) = P(X = x, Y = y) = Y = X = 0 1 2 1/45 6/45 3/45 0 1 10/45 15/45 0 2 10/45 0 0 (a) Find the covariance of X and Y. (b) Find the correlation between X and Y.
For questions 54-57, consider the following experiment:
A small department has 10 faculty members of whom 3 are assistant professors (aP), 5 are associate
professors (AP), and 2 are professors (P). Of these 10 faculty members, 2 are randomly selected to be
on a committee. Let X denote the number of aP selected and let Y denote the number of AP selected.
X and Y are jointly discrete random variables with mass points (x, y) = {(0, 0), (0, 1), (0, 2), (1, 0), (1, 1), (2,0)}.
Moreover, we can find the probability associated with each of these mass points as follows:
(3²)
ƒ(0,0) = P(X = 0, Y = 0) = P(2 P selected) =
f(0, 1) = P(X=0, Y = 1) = P(1 P, 1 AP selected)
= P(X = 2, Y = 0) = P(2 aP selected)
Leading to the joint pmf: f(x, y) = P(X = x, Y = y) =
X = Number of aP chosen
0
1
1/45 6/45
10/45 f(1,1)
0
10/45
Y = Number of AP chosen 0
1
2
2
3/45
0
0
=
=
15
(6)
=1000
=
Transcribed Image Text:For questions 54-57, consider the following experiment: A small department has 10 faculty members of whom 3 are assistant professors (aP), 5 are associate professors (AP), and 2 are professors (P). Of these 10 faculty members, 2 are randomly selected to be on a committee. Let X denote the number of aP selected and let Y denote the number of AP selected. X and Y are jointly discrete random variables with mass points (x, y) = {(0, 0), (0, 1), (0, 2), (1, 0), (1, 1), (2,0)}. Moreover, we can find the probability associated with each of these mass points as follows: (3²) ƒ(0,0) = P(X = 0, Y = 0) = P(2 P selected) = f(0, 1) = P(X=0, Y = 1) = P(1 P, 1 AP selected) = P(X = 2, Y = 0) = P(2 aP selected) Leading to the joint pmf: f(x, y) = P(X = x, Y = y) = X = Number of aP chosen 0 1 1/45 6/45 10/45 f(1,1) 0 10/45 Y = Number of AP chosen 0 1 2 2 3/45 0 0 = = 15 (6) =1000 =
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