54. A card-dealing machine deals spades (1), hearts (2), dubs (3), and diamonds (4) at random as if from an infinite dedk. In randomness dcheck, 1,600 cards were dealt and counted. The results are shown below. Sult Observed Spades Hearts Clubs Diamonds To test if the poker-dealing machine deals cards at random, the null and alternative hypotheses are A Ho: Pi P2 = p3 p4 0, HA: Not all population proportions are equal to 0,25 B. Ho: P1 P2 = p3 P4 0.25, HA: Not all population proportions are equal to 0,25 C. Ho: P1 p2 = p3 p4 1, HA: Not all population proportions are equal to 0,25 D. Họ: Pi = P2 = P3 = p4 0.20, HA: Not all population proportions are equal to 0,20 410 405 370 415 %3D %3D %3D %3D
54. A card-dealing machine deals spades (1), hearts (2), dubs (3), and diamonds (4) at random as if from an infinite dedk. In randomness dcheck, 1,600 cards were dealt and counted. The results are shown below. Sult Observed Spades Hearts Clubs Diamonds To test if the poker-dealing machine deals cards at random, the null and alternative hypotheses are A Ho: Pi P2 = p3 p4 0, HA: Not all population proportions are equal to 0,25 B. Ho: P1 P2 = p3 P4 0.25, HA: Not all population proportions are equal to 0,25 C. Ho: P1 p2 = p3 p4 1, HA: Not all population proportions are equal to 0,25 D. Họ: Pi = P2 = P3 = p4 0.20, HA: Not all population proportions are equal to 0,20 410 405 370 415 %3D %3D %3D %3D
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Contingency Table
A contingency table can be defined as the visual representation of the relationship between two or more categorical variables that can be evaluated and registered. It is a categorical version of the scatterplot, which is used to investigate the linear relationship between two variables. A contingency table is indeed a type of frequency distribution table that displays two variables at the same time.
Binomial Distribution
Binomial is an algebraic expression of the sum or the difference of two terms. Before knowing about binomial distribution, we must know about the binomial theorem.
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Question
![54. A card-dealing machine deals spades (1), hearts (2), dubs (3), and diamonds (4) at random
as if from an infinite deck. In randomness check, 1,600 cards were dealt and counted. The
results are shown below.
Sult
Observed
Spades
Hearts
410
405
Clubs
370
Diamonds
415
To test if the poker-dealing machine deals cards at random, the null and alternative
hypotheses are
A. Ho: P1 P2 = P3 = P4 = 0, HA: Not all population proportions are equal to 0,25
B. Ho: P1 = P2 = P3 = P4 = 0.25, HA: Not all population proportions are equal to 0,25
C. Ho: P1 = P2 = p3 = P4 = 1, HA: Not all population proportions are equal to 0,25
D. Ho: P1 = P2 = P3 = p. = 0.20, HA: Not all population proportions are equal to 0,20
%3D
%3D
%3D
55. A university has six colleges and takes a poll to gauge student support for a tuition increase.
The university wants to ensure each college is represented fairly. The below table shows the
observed number of students who participate in the poll from each college and the actual
proportion of students in each college.
College
Proportion
o20
Observed,
1.
457
2.
206
0.08
792
0.29
336
015
373
015
For the goodness-of-fit test, the assumed degrees of freedom are
A. 2
В. 3
C. 4
D. 5
56. For the chi-square test of a contingency table, the expected cell frequencies are found as
A. the row total multiplied by the column total divided by the sample size
B. the observed cell frequency
C. (r-1)(c-1)
D. rC](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa88a3b9f-23e4-4dca-b7ff-c63ebbe00473%2Fe644d114-1d7b-457c-809e-bfabdc0ebd17%2F4p9fc5d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:54. A card-dealing machine deals spades (1), hearts (2), dubs (3), and diamonds (4) at random
as if from an infinite deck. In randomness check, 1,600 cards were dealt and counted. The
results are shown below.
Sult
Observed
Spades
Hearts
410
405
Clubs
370
Diamonds
415
To test if the poker-dealing machine deals cards at random, the null and alternative
hypotheses are
A. Ho: P1 P2 = P3 = P4 = 0, HA: Not all population proportions are equal to 0,25
B. Ho: P1 = P2 = P3 = P4 = 0.25, HA: Not all population proportions are equal to 0,25
C. Ho: P1 = P2 = p3 = P4 = 1, HA: Not all population proportions are equal to 0,25
D. Ho: P1 = P2 = P3 = p. = 0.20, HA: Not all population proportions are equal to 0,20
%3D
%3D
%3D
55. A university has six colleges and takes a poll to gauge student support for a tuition increase.
The university wants to ensure each college is represented fairly. The below table shows the
observed number of students who participate in the poll from each college and the actual
proportion of students in each college.
College
Proportion
o20
Observed,
1.
457
2.
206
0.08
792
0.29
336
015
373
015
For the goodness-of-fit test, the assumed degrees of freedom are
A. 2
В. 3
C. 4
D. 5
56. For the chi-square test of a contingency table, the expected cell frequencies are found as
A. the row total multiplied by the column total divided by the sample size
B. the observed cell frequency
C. (r-1)(c-1)
D. rC
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