**52. The drawing shows a container that is partially filled with 2.0 gramsof water. The temperature is maintained at a constant 20 °C. The spaceabove the liquid contains air that is completely saturated with water vapor.A tube of length 0.15 m and cross-sectional area 3.0 X 10-ª m² connectsthe water vapor at one end to air that remains completely dry at the otherend. The diffusion constant for water vapor in air is 2.4× 10-5 m²/s. Howlong does it take for the water in the container to evaporate completely?(Hint: Refer to Problem 75 in Chapter 12 to find the pressure of the watervapor.)- 0.15 m-Water- Dry airvaporLiquid water

Given: Mass of water = 2 g =2×10-3 kg Temperature = 20° C = 293.15 K Length of tube L =0.15 m Cross…

Answered: **52. The drawing shows a container…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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The initial temperature of three moles of oxygen gas is 33.5°C, and its pressure is 7.80 atm. (a) What will its final temperature be when heated at constant volume so the pressure is two times its initial value? °C (b) Now the volume of the gas is also allowed to change. Determine the final temperature if the gas is heated until the pressure and the volume are doubled. °C
Pr4. The pressure of an ideal gas in a closed rigid container is 0.6 atm at 35 degrees C. The number of molecules is 5×1022 (one mole of gas contains 6 x 1023 molecules and 1 atm = 1.01 × 105 Pa) a) What is the pressure in Pa and temperature in K of the gas? b) How many moles of gas is in the container? c) What is the volume of the container? d) If the container is heated to 120 degrees C, and volume remains the same what is the pressure of the gas in atm?
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Consider two containers with the same volume and temperature. The first container is labelled "Dry" and holds "dry" air = a ratio of nitrogen (N2) and oxygen (O2). The second container is labelled "Humid" and holds "moist" air = the SAME ratio of nitrogen and oxygen, but also contains water (H2O) vapor. According to the ideal gas law, if the pressures are equal, the weight of the gas inside the "Dry" container will be
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A cell doesn’t need a circulatory system, but your body does. Let’s do a quick calculation to see why. A typical cell has a diameter of 10 mm. The smallest mammals in the world, shrews, are about 10 μm across. Compute the diffusion time for oxygen molecules through water at 25°C for these two distances.
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There are 1.5 times as many molecules as Avogadro's number at a temperature of 2.1°C inside a sealed cube with dimensions 3.0 cm ✕ 3.0 cm ✕ 3.0 cm. How much force does the gas exert on one of the walls of the cube?
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