**Diffusion of Carbon Tetrachloride (CCl₄) in Benzene (C₆H₆)**Carbon tetrachloride (CCl₄) is diffusing through benzene (C₆H₆), as the illustration shows. The concentration of CCl₄ at the left end of the tube is maintained at 1.09 × 10⁻² kg/m³, and the diffusion constant is 23.4 × 10⁻¹⁰ m²/s. The CCl₄ enters the tube at a mass rate of 4.38 × 10⁻¹³ kg/s. Using these data and the information presented in the drawing, calculate:(a) the mass of CCl₄ per second that passes point A(b) the concentration of CCl₄ at point A**Diagram Description:**- The diagram presents a cylindrical tube through which CCl₄ is diffusing.- Key dimensions and information include: - The distance from the left end to point A inside the tube is 5.00 × 10⁻³ m. - The cross-sectional area of the tube is 3.00 × 10⁻⁴ m².**Calculations:**(a) **Mass of CCl₄ per second at point A:**- Enter the number and select the appropriate units for the mass rate.(b) **Concentration of CCl₄ at point A:**- Enter the number and select the appropriate units for concentration.Utilize the given data to apply Fick’s laws of diffusion for determining the mass flow and concentration changes along the tube.

Solution:-The mass flow rate at which CCI4 enters the left end of the tube is the same as the mass…

Carbon tetrachloride (CCl4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.09 x 10-2 kg/m³, and the diffusion constant is 23.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.38 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. 5.00 x 10-³ m -CCI4 Cross-sectional area = 3.00 x 10-4 m²

Carbon tetrachloride (CCl4) is diffusing through benzene (C6H6), as the drawing illustrates. The concentration of CCl4 at the left end of the tube is maintained at 1.09 x 10-2 kg/m³, and the diffusion constant is 23.4 x 10-10 m²/s. The CCl4 enters the tube at a mass rate of 4.38 x 10-13 kg/s. Using these data and those shown in the drawing, find (a) the mass of CCl4 per second that passes point A and (b) the concentration of CCl4 at point A. 5.00 x 10-³ m -CCI4 Cross-sectional area = 3.00 x 10-4 m²

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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**Diffusion of Carbon Tetrachloride (CCl₄) in Benzene (C₆H₆)**

Carbon tetrachloride (CCl₄) is diffusing through benzene (C₆H₆), as the illustration shows. The concentration of CCl₄ at the left end of the tube is maintained at 1.09 × 10⁻² kg/m³, and the diffusion constant is 23.4 × 10⁻¹⁰ m²/s. The CCl₄ enters the tube at a mass rate of 4.38 × 10⁻¹³ kg/s. Using these data and the information presented in the drawing, calculate:

(a) the mass of CCl₄ per second that passes point A
(b) the concentration of CCl₄ at point A

**Diagram Description:**

- The diagram presents a cylindrical tube through which CCl₄ is diffusing.
- Key dimensions and information include:
- The distance from the left end to point A inside the tube is 5.00 × 10⁻³ m.
- The cross-sectional area of the tube is 3.00 × 10⁻⁴ m².

**Calculations:**

(a) **Mass of CCl₄ per second at point A:**
- Enter the number and select the appropriate units for the mass rate.

(b) **Concentration of CCl₄ at point A:**
- Enter the number and select the appropriate units for concentration.

Utilize the given data to apply Fick’s laws of diffusion for determining the mass flow and concentration changes along the tube.

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