50.0mL of 2.2 M HCl is combined with 50.0 mL of 2.0 M NaOH in a coffee-cup calorimeter. Calculate the moles of HCl added to the calorimeter.

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Chapter1: Chemical Foundations
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**Question 1**

50.0 mL of 2.2 M HCl is combined with 50.0 mL of 2.0 M NaOH in a coffee-cup calorimeter. 

Calculate the moles of HCl added to the calorimeter. 

[Answer Box]

---

**Explanation:**

This problem involves a reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) in a calorimeter setup. To find the moles of HCl added, use the formula:

\[
\text{Moles of HCl} = \text{Volume (L)} \times \text{Molarity (M)}
\]

Convert the 50.0 mL of HCl to liters by dividing by 1000:

\[
50.0 \, \text{mL} = 0.050 \, \text{L}
\]

Then, multiply by the molarity:

\[
\text{Moles of HCl} = 0.050 \, \text{L} \times 2.2 \, \text{M}
\]
Transcribed Image Text:**Question 1** 50.0 mL of 2.2 M HCl is combined with 50.0 mL of 2.0 M NaOH in a coffee-cup calorimeter. Calculate the moles of HCl added to the calorimeter. [Answer Box] --- **Explanation:** This problem involves a reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH) in a calorimeter setup. To find the moles of HCl added, use the formula: \[ \text{Moles of HCl} = \text{Volume (L)} \times \text{Molarity (M)} \] Convert the 50.0 mL of HCl to liters by dividing by 1000: \[ 50.0 \, \text{mL} = 0.050 \, \text{L} \] Then, multiply by the molarity: \[ \text{Moles of HCl} = 0.050 \, \text{L} \times 2.2 \, \text{M} \]
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