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4. 3. TCactions, Wilere M represents à generic metal. 1. 2 M(s) + 6 HCl(aq) → 2 MCl, (aq) + 3 H, (g) AH1 = -847.0 kJ %3D 2. HCl(g) → HCI(aq) AH2 = -74.8 kJ %3D H, (g) + Cl,(g) –→ 2 HCl(g) AH3 = -1845.0 kJ %3D MCI, (s) → MCI, (aq) AH4 = -424.0 kJ | Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 Cl,(g)→ 2 MCI,(s) ΔΗ-

4. 3. TCactions, Wilere M represents à generic metal. 1. 2 M(s) + 6 HCl(aq) → 2 MCl, (aq) + 3 H, (g) AH1 = -847.0 kJ %3D 2. HCl(g) → HCI(aq) AH2 = -74.8 kJ %3D H, (g) + Cl,(g) –→ 2 HCl(g) AH3 = -1845.0 kJ %3D MCI, (s) → MCI, (aq) AH4 = -424.0 kJ | Use the given information to determine the enthalpy of the reaction 2 M(s) + 3 Cl,(g)→ 2 MCI,(s) ΔΗ-

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Determining Enthalpy of a Reaction** Consider these reactions, where M represents a generic metal: 1. \( 2M(s) + 6HCl(aq) \rightarrow 2MCl_3(aq) + 3H_2(g) \) ΔH\(_1\) = -847.0 kJ 2. \( HCl(g) \rightarrow HCl(aq) \) ΔH\(_2\) = -74.8 kJ 3. \( H_2(g) + Cl_2(g) \rightarrow 2HCl(g) \) ΔH\(_3\) = -1845.0 kJ 4. \( MCl_3(s) \rightarrow MCl_3(aq) \) ΔH\(_4\) = -424.0 kJ --- **Objective:** Use the given information to determine the enthalpy of the reaction: \[ 2M(s) + 3Cl_2(g) \rightarrow 2MCl_3(s) \] --- **Calculation:** To find the enthalpy change (ΔH) for the target reaction, apply Hess's law using the provided reaction enthalpies. The solution involves algebraically combining these reactions to match the target equation and summing their respective ΔH values. \[ \boxed{\Delta H =} \]
Transcribed Image Text:**Determining Enthalpy of a Reaction** Consider these reactions, where M represents a generic metal: 1. \( 2M(s) + 6HCl(aq) \rightarrow 2MCl_3(aq) + 3H_2(g) \) ΔH\(_1\) = -847.0 kJ 2. \( HCl(g) \rightarrow HCl(aq) \) ΔH\(_2\) = -74.8 kJ 3. \( H_2(g) + Cl_2(g) \rightarrow 2HCl(g) \) ΔH\(_3\) = -1845.0 kJ 4. \( MCl_3(s) \rightarrow MCl_3(aq) \) ΔH\(_4\) = -424.0 kJ --- **Objective:** Use the given information to determine the enthalpy of the reaction: \[ 2M(s) + 3Cl_2(g) \rightarrow 2MCl_3(s) \] --- **Calculation:** To find the enthalpy change (ΔH) for the target reaction, apply Hess's law using the provided reaction enthalpies. The solution involves algebraically combining these reactions to match the target equation and summing their respective ΔH values. \[ \boxed{\Delta H =} \]
Expert Solution
Step 1

Consider the given reactions.

2Ms+6HClaq→2MCl3aq+3H2g                ∆H1=-847 kJHClg→HClaq                                                ∆H2=-74.8 kJ

H2g+Cl2g→2HClg                       ∆H3=-1845 kJMCl3s→MCl3aq                                ∆H4=-424 kJ

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