50.0 2 12.0 mH 20.0 V 18.0 mH 25.0 2 15.0 mH 0000

icon
Related questions
Question

In the circuit shown in
Fig. , the switch S has been open
for a long time and is suddenly closed.
Neither the battery nor the inductors
have any appreciable resistance. What
do the ammeter and the voltmeter read
(a) just after S is closed; (b) after S has
been closed a very long time; (c) 0.115
ms after S is closed? 

50.0 2
12.0 mH
20.0 V
18.0 mH
25.0 2
15.0 mH
0000
Transcribed Image Text:50.0 2 12.0 mH 20.0 V 18.0 mH 25.0 2 15.0 mH 0000
Expert Solution
Step 1

Given data:

  • The resistance is R1=50 Ω.
  • The resistance is R2=25 Ω.
  • The voltage is ε=20 V.
  • The inductance is L1=18 mH.
  • The inductance is L2=12 mH.
  • The inductance is L3=15 mH.
  • The time is t=0.115 ms.

Since L2 and L3 are in series. Thus, the equivalent inductance will be:

Leq=L2+L3Leq=12 mH+15 mHLeq=27 mH

Since Leq is in parallel connection with L1. Thus, the equivalent inductance will be:

L=1L1+1Leq-1L=118 mH+127 mH-1L=10.8 mH

steps

Step by step

Solved in 2 steps

Blurred answer
Similar questions