50.0 0 12.0 mH 20.0 V :18.0 mH 15.0 mH 25.0 N A
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In the circuit shown in Fig., the switch S has been open for a long time and is suddenly closed. Neither the battery nor the inductors have any appreciable resistance. What do the ammeter and the voltmeter read (a) just after S is closed; (b) after S has been closed a very long time; (c) 0.115 ms after S is closed?


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- Just as every circuit has a small amount of extra resistance in the wires, which we usually neglect, every circuit also has a small amount of stray capacitance and self-inductance because of the geometry of the wires. Consider a pacemaker implant in which the leads travel close together from the device to the heart, then separate and connect to the top and bottom of the heart. The circuit completes through the middle of the heart, so take the area of the current loop to be half the cross-sectional area of the heart. The current loop is approximately a circle of radius 4.0 cm. Approximate the magnetic field as constant inside the loop and equal to the value at the center of the loop. Use this field to get the magnetic flux through the loop and hence estimate the stray self-inductance L of the loop. L% = x10 H.A transformer is to be used to provide power for a computer disk drive that needs 5.6 V (rms) instead of the 120 V (rms) from the wall outlet. The number of turns in the primary is 420, and it delivers 500 mA (the secondary current) at an output voltage of 5.6 V (rms). (a) Should the transformer have more turns in the secondary compared to the primary, or fewer turns? O There should be more turns in the secondary. O There should be fewer turns in the secondary. (b) Find the current in the primary. (c) Find the number of turns in the secondary. turnsIn the RL circuit shown below, it takes 1.5 seconds after the switch is closed for the current to reach half of its steady-state value. If the inductor was replaced with an inductor with twice the inductance and the experiment was run again from the beginning, how long would it take for the current to reach half of its steady-state value?
- Time t < 0, the circuit is in DC Steady State. The switch is opened instantly at time t=0. This question deals with the new initial conditions for t>0. When t<0, I₂ = 7 A, and I₃ = 9 A. Give I₂ at t=0+ (at t=0, but after the switch is opened).An inductor consists of 100 turns of wire tightly wound about an insulating core. It is attached to a power supply and when the current through it is increased from 0 to 5 A in 3, s an induced emf of 5 V is measured. Find the inductance of this device and the magnetic flux and the energy stored in the magnetic field when the current is held steady at 5 A.The circuit was in DC steady state for t < 0. A quantity absolutely cannot change suddenly in this circuit, and in general unless nothing else can happen. It must be continuous across the switch opening. Which is that quantity? (The battery voltage also remains constant; that's not the answer I'm looking for.) Please see photos for more details
- ℇ = 100 V, R = 20.0 Ω, and L = 100.0 mH. The switch is closed att = 0. (a) What is the time constant of the circuit shown below? (b) Find the currentat t = 0.050 sec, (c) at what time the current is 40% of its maximum value?The heating coils in a hair dryer are 0.87 cm in diameter, have a combined length of 0.8 m, and a total of 480 turns. (a) What is their total self-inductance assuming they act like a single solenoid? (b) How much energy is stored in them when 6.5 A flows?Consider the circuit in the figure below, taking & = S + R ww ele 6.00 V, L = 7.20 mH, and R = 7.20 0. (a) What is the inductive time constant of the circuit? ms (b) Calculate the current in the circuit 250 µs after the switch is closed. A (c) What is the value of the final steady-state current? A (d) After what time interval does the current reach 80.0% of its maximum value? ms