F46. 5.50 g of As₂O3 are titrated with 33.5 mL of KMnO4 to reach the end point.5 As₂O3(s) + 4 MnO (aq) + 9 H₂O(l) + 12 H* (aq) → 10 H3 AsO₂ (aq) + 4 Mn² + (aq)Calculate the concentration of the KMnO4 solution.[KMnO4] =M

Given -> Weight of Ag2O3 = 5.50 gm Volume of KMnO4 = 33.5 ml = 0.0335 L (1L = 1000ml)

5.50 g of As₂O3 are titrated with 33.5 mL of KMnO4 to reach the end point. 5 As₂O3(s) + 4 MnO4 (aq) + 9 H₂O(l) + 12 H* (aq) → 10 H3 AsO (aq) + 4 Mn² *(aq) Calculate the concentration of the KMnO4 solution. [KMnO4] = M

5.50 g of As₂O3 are titrated with 33.5 mL of KMnO4 to reach the end point. 5 As₂O3(s) + 4 MnO4 (aq) + 9 H₂O(l) + 12 H* (aq) → 10 H3 AsO (aq) + 4 Mn² *(aq) Calculate the concentration of the KMnO4 solution. [KMnO4] = M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

F46.

5.50 g of As₂O3 are titrated with 33.5 mL of KMnO4 to reach the end point.
5 As₂O3(s) + 4 MnO (aq) + 9 H₂O(l) + 12 H* (aq) → 10 H3 AsO₂ (aq) + 4 Mn² + (aq)
Calculate the concentration of the KMnO4 solution.
[KMnO4] =
M

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