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5.37 Determine the output of the summing amplifier 2 V + 3 V +- 10 km2 ww 20 ks2 30 km2 ww 30 ks2 www. 1 + 9 + 210-411

5.37 Determine the output of the summing amplifier 2 V + 3 V +- 10 km2 ww 20 ks2 30 km2 ww 30 ks2 www. 1 + 9 + 210-411

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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### Summing Amplifier Circuit Analysis **Figure 5.37: Summing Amplifier Configuration** This image shows a summing amplifier circuit using three voltage inputs connected to an operational amplifier (op-amp). The op-amp is configured as an inverting summing amplifier. #### Circuit Components: 1. **Input Voltages:** - **1 V** connected through a **10 kΩ** resistor. - **2 V** connected through a **20 kΩ** resistor. - **3 V** connected through a **30 kΩ** resistor. 2. **Feedback Resistor:** - **30 kΩ** resistor connected from the output to the inverting input of the op-amp. 3. **Op-Amp Configuration:** - The op-amp is shown with the inverting input connected to summing junctions of the input resistors. #### Operation: The output voltage (\( V_o \)) of the summing amplifier can be calculated using the principle of superposition and the formula for an inverting summing amplifier: \[ V_o = - \left( \frac{V_1}{R_1} + \frac{V_2}{R_2} + \frac{V_3}{R_3} \right) \times R_f \] Where: - \( V_1, V_2, V_3 \) are the input voltages. - \( R_1, R_2, R_3 \) are the resistors associated with each input voltage. - \( R_f \) is the feedback resistor. Substituting the given values: - \( V_1 = 1 \, \text{V}, R_1 = 10 \, \text{k}\Omega \) - \( V_2 = 2 \, \text{V}, R_2 = 20 \, \text{k}\Omega \) - \( V_3 = 3 \, \text{V}, R_3 = 30 \, \text{k}\Omega \) - \( R_f = 30 \, \text{k}\Omega \) \[ V_o = - \left( \frac{1}{10} + \frac{2}{20} + \frac{3}{30} \right) \times 30 \] \[ V_o = - (0.1 + 0
Transcribed Image Text:### Summing Amplifier Circuit Analysis **Figure 5.37: Summing Amplifier Configuration** This image shows a summing amplifier circuit using three voltage inputs connected to an operational amplifier (op-amp). The op-amp is configured as an inverting summing amplifier. #### Circuit Components: 1. **Input Voltages:** - **1 V** connected through a **10 kΩ** resistor. - **2 V** connected through a **20 kΩ** resistor. - **3 V** connected through a **30 kΩ** resistor. 2. **Feedback Resistor:** - **30 kΩ** resistor connected from the output to the inverting input of the op-amp. 3. **Op-Amp Configuration:** - The op-amp is shown with the inverting input connected to summing junctions of the input resistors. #### Operation: The output voltage (\( V_o \)) of the summing amplifier can be calculated using the principle of superposition and the formula for an inverting summing amplifier: \[ V_o = - \left( \frac{V_1}{R_1} + \frac{V_2}{R_2} + \frac{V_3}{R_3} \right) \times R_f \] Where: - \( V_1, V_2, V_3 \) are the input voltages. - \( R_1, R_2, R_3 \) are the resistors associated with each input voltage. - \( R_f \) is the feedback resistor. Substituting the given values: - \( V_1 = 1 \, \text{V}, R_1 = 10 \, \text{k}\Omega \) - \( V_2 = 2 \, \text{V}, R_2 = 20 \, \text{k}\Omega \) - \( V_3 = 3 \, \text{V}, R_3 = 30 \, \text{k}\Omega \) - \( R_f = 30 \, \text{k}\Omega \) \[ V_o = - \left( \frac{1}{10} + \frac{2}{20} + \frac{3}{30} \right) \times 30 \] \[ V_o = - (0.1 + 0
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