V₁ R Answer: Consider the network above with V₁ = 9V, V₂ = 11V, and R = 1.2kQ. Treat the op-amp as real, with ß = 2 × 105. R₂ = 3MQ, and R.₁. = 750. a. What is the voltage v. across the input terminals? Answer: + 3R b. What is the current i through the input terminals? Answer: + Vout c. What is the "ideal" output voltage (treating the op-amp as ideal)? Answer: d. What is the difference between the ideal and real output voltage? (Compute Vreal - Videal.) (For (a). enter 8 digits of precision. For the rest, enter 4 digits.)
V₁ R Answer: Consider the network above with V₁ = 9V, V₂ = 11V, and R = 1.2kQ. Treat the op-amp as real, with ß = 2 × 105. R₂ = 3MQ, and R.₁. = 750. a. What is the voltage v. across the input terminals? Answer: + 3R b. What is the current i through the input terminals? Answer: + Vout c. What is the "ideal" output voltage (treating the op-amp as ideal)? Answer: d. What is the difference between the ideal and real output voltage? (Compute Vreal - Videal.) (For (a). enter 8 digits of precision. For the rest, enter 4 digits.)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![The diagram illustrates an op-amp circuit with input voltages \( V_1 \) and \( V_2 \), with resistors labeled \( R \) and \( 3R \). It depicts an inverting amplifier configuration. The output voltage \( v_{\text{out}} \) is shown at the op-amp's output terminal.
Conditions provided:
- \( V_1 = 9V \)
- \( V_2 = 11V \)
- \( R = 1.2k\Omega \)
The op-amp is treated as real with the following parameters:
- Open-loop gain (\( \beta \)) = \( 2 \times 10^5 \)
- Input resistance (\( R_x \)) = 3M\(\Omega\)
- Output resistance (\( R_y \)) = 75\(\Omega\)
Questions:
a. What is the voltage \( v_x \) across the input terminals?
- Answer: [__________] (Enter 8 digits of precision)
b. What is the current \( i_x \) through the input terminals?
- Answer: [__________] (Enter 4 digits of precision)
c. What is the "ideal" output voltage (treating the op-amp as ideal)?
- Answer: [__________] (Enter 4 digits of precision)
d. What is the difference between the ideal and real output voltage? (Compute \( v_{\text{real}} - v_{\text{ideal}} \))
- Answer: [__________] (Enter 4 digits of precision)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F178d4f16-e840-47df-a2f3-a1f3117db472%2Fdedba7ed-7d36-4929-9482-5371bcdfe987%2F47i1uiw_processed.png&w=3840&q=75)
Transcribed Image Text:The diagram illustrates an op-amp circuit with input voltages \( V_1 \) and \( V_2 \), with resistors labeled \( R \) and \( 3R \). It depicts an inverting amplifier configuration. The output voltage \( v_{\text{out}} \) is shown at the op-amp's output terminal.
Conditions provided:
- \( V_1 = 9V \)
- \( V_2 = 11V \)
- \( R = 1.2k\Omega \)
The op-amp is treated as real with the following parameters:
- Open-loop gain (\( \beta \)) = \( 2 \times 10^5 \)
- Input resistance (\( R_x \)) = 3M\(\Omega\)
- Output resistance (\( R_y \)) = 75\(\Omega\)
Questions:
a. What is the voltage \( v_x \) across the input terminals?
- Answer: [__________] (Enter 8 digits of precision)
b. What is the current \( i_x \) through the input terminals?
- Answer: [__________] (Enter 4 digits of precision)
c. What is the "ideal" output voltage (treating the op-amp as ideal)?
- Answer: [__________] (Enter 4 digits of precision)
d. What is the difference between the ideal and real output voltage? (Compute \( v_{\text{real}} - v_{\text{ideal}} \))
- Answer: [__________] (Enter 4 digits of precision)
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