5.0 иF 10.0 мF 9.0 дF a 8.0 иF
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Figure shows a
system of four capacitors, where
the potential difference across ab
is 50.0 V. (a) Find the equivalent
capacitance of this system between
a and b. (b) How much charge is
stored by this combination of capacitors?
(c) How much charge is
stored in each of the 10.0 mF and
the 9.0 mF capacitors?
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- ER Find the total capacitance of the combination of capacitors shown in the figure below. (C, = 30.5 µF, C, = 5.66 µF. Enter your answer tó three decimal places.) 0.300 µFThree copocitocs ore connected as shown in the figure. Ihe Capacitors all have +he some dielectric material and The above Copacitonce Values include the dielectric effect, 2UF a CE a What is the equivalent copacitonce between a ond 6? 6, If there is a voltoge of 1ov between a ond b. what is the charge on the 2 UF capacitor? C. For case (b), what is the Voltage across the 4uF Capacitor? d. Suppose now we take the 4e F copacitor from where it is ond put all three capacitors in series. Because of the dielectrics used, each copacitor will break down if the potentia) exceeds 60 V. What is the maxinum Voltage that Can be applied across a ond b in this case without breaking down ony of the Capacitors?A dielectric- filled por allel-plate capacitor as pleite area A=10.0cm²,plate separation d= 8.00 mm an K = 4•00. The capacitor is connected to a battery oltage V= 5•00 V Throughout nd dieleitric tonštad that creates a the problem, use constant ve -12 U, of the dielect erically in joules d मास्पु Find the ric - filled copacitor energy つ) मा र #he txpress your an Swer nu 2 The dielectric plaite i's now slewly pulled eut of the capacater, which rencains connected to the battery. tind the energy Uz ator at the moment when the Lapecitor is capa half-filled with Hhe dielectric. Express your answers nuimerically in joules 3.The capecitor s Row disconnected from the battery and the dielectric plate is slowly removed the rest ef Hhe way out ef the capacitor. find the new enerqy ef he capecitor Ug Express your answers ruemerically ie joules 4.J0the the dielectric from the disconnected work Wis done by e exter nal ager frocess of removing The remaining pertion ef the capacitor, how much nt ating…
- What is the capacitance of a parallel-plate capacitor made of two square alumimm plates that are 4.0 cm in lenth on each side and are seperated by 5.0 mm?MY YSY When an air-filled parallel-plate capacitor is connected to a 28 V battery, it contains 80 µC of charge. After disconnecting the capacitor from the battery, the distance between two parallel plates is now reduced to half. (a) What is its new capacitance? Cnew µF %3D (b) What is the new potential difference between two plates? Vnew volts (c) Find the energy stored in the new capacitor. Unew %3DFill in the blanks: Three capacitors with 25 F, 50 F, and 33 F capacitance were arranged in series. The total capacitance is farads.
- A capacitor is composed of 2 plates separated by a sheet öf insulatih and of relative permittivity 4. The distance between the plates is increased to allow the insertion of a second sheet of 5mm thick and of relative permittivity &,. If the equivalent capacitance is one third of the original capacitance, find the value of ɛ,.Six Q.4: Eour capacitors are arranged in the following configuration: the capacitances of capacitors are C1= 1.5µF, C2= 3.5µF, C3= 2.0µF, C4= 2.5µF, Cs= 3.0µF and C6=4.0µF. The voltage V of the battery is 12.0V. (a) Calculate the capacitance of the configuration. (b) How much energy is stored in the configuration? (c) How much energy is stored in capacitor C1? C2 C3 C1